帮我用c语言写一段代码,要求如下:/** * @brief * * @param s The address of the first character in a CS. * @param len The length (number of character) is the CS. * @param graph A Bool value (TRUE or FALSE). * @return The characters are printed one by one. If graph is TRUE, then each character is printed in its visual form, i.e., using printf with %c; otherwise, each character is printed by its number value, i.e., using printf with %d. Nothing is returned. * @note This function can be used to show the content of a piece of memory. * @note It is possible that when printing the elements in the CS, they can be separated by some way, like by a space or a comma, etc. */
时间: 2023-02-06 14:07:57 浏览: 837
A Brief Review of ChatGPT: Its Value and the Underlying GPT Tech
好的,以下是示例代码:
```
void show_cs(const char *s, int len, bool graph)
{
for (int i = 0; i < len; i++)
{
if (graph)
{
printf("%c", s[i]);
}
else
{
printf("%d", s[i]);
}
}
}
```
这段代码接受三个参数:
- `s`:指向 CS 第一个字符的地址
- `len`:CS 的长度(即字符数)
- `graph`:一个布尔值(TRUE 或 FALSE)
它会依次打印出 CS 中的字符,如果 `graph` 为 TRUE,则使用 `printf` 函数的 `%c` 格式化字符来打印每个字符;如果 `graph` 为 FALSE,则使用 `printf` 函数的 `%d` 格式化字符来打印字符的数字值。这个函数不会返回任何值。
注意:使用这个函数可以显示内存块的内容。也可以在打印 CS 中的元素时使用某种方式将它们分隔开,例如使用空格或逗号等。
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