两路合并排序算法c++

下面是一个简单的 C++ 实现合并排序算法的代码：

#include <iostream>
#include <vector>

using namespace std;

void merge(vector<int>& nums, int left, int mid, int right) {
    vector<int> temp(right - left + 1);
    int i = left, j = mid + 1, k = 0;
    while (i <= mid && j <= right) {
        if (nums[i] <= nums[j]) {
            temp[k++] = nums[i++];
        } else {
            temp[k++] = nums[j++];
        }
    }
    while (i <= mid) {
        temp[k++] = nums[i++];
    }
    while (j <= right) {
        temp[k++] = nums[j++];
    }
    for (int p = 0; p < temp.size(); p++) {
        nums[left + p] = temp[p];
    }
}

void mergeSort(vector<int>& nums, int left, int right) {
    if (left >= right) return;
    int mid = left + (right - left) / 2;
    mergeSort(nums, left, mid);
    mergeSort(nums, mid + 1, right);
    merge(nums, left, mid, right);
}

int main() {
    vector<int> nums = {9, 7, 8, 3, 2, 1, 5, 4, 6};
    mergeSort(nums, 0, nums.size() - 1);
    for (int num : nums) {
        cout << num << " ";
    }
    cout << endl;
    return 0;
}

该算法时间复杂度为 $O(n \log n)$，其中 $n$ 为待排序数组的长度。