我有一个ls_order的表下面有这些字段 订单负责人 sales_person_id 订单成交价 price 订单创建时间 created_time 我要根据created_time 计算出 当天，当周，当月，当天分别销售额，并根据sales_person_id 分组，我想用一条sql实现怎么编写sql

可以使用以下SQL语句：

SELECT 
    sales_person_id,
    SUM(CASE 
        WHEN created_time >= DATE(NOW()) AND created_time < DATE(NOW()) + INTERVAL 1 DAY 
        THEN price 
        ELSE 0 
    END) AS daily_sales_amount,
    SUM(CASE 
        WHEN YEARWEEK(created_time) = YEARWEEK(NOW()) 
        THEN price 
        ELSE 0 
    END) AS weekly_sales_amount,
    SUM(CASE 
        WHEN YEAR(created_time) = YEAR(NOW()) AND MONTH(created_time) = MONTH(NOW()) 
        THEN price 
        ELSE 0 
    END) AS monthly_sales_amount,
    SUM(CASE 
        WHEN created_time >= DATE(NOW()) AND created_time < DATE(NOW()) + INTERVAL 1 DAY 
        THEN price 
        WHEN YEARWEEK(created_time) = YEARWEEK(NOW()) 
        THEN price 
        WHEN YEAR(created_time) = YEAR(NOW()) AND MONTH(created_time) = MONTH(NOW()) 
        THEN price 
        ELSE 0 
    END) AS total_sales_amount
FROM 
    ls_order
GROUP BY 
    sales_person_id;

这个SQL语句将会按照销售人员对订单进行分组，并使用 `SUM` 聚合函数计算每天、每周、每月和总销售额。其中，`CASE` 语句用于根据 `created_time` 字段判断订单是否属于当天、当周、当月或总销售额，并将相应的销售额累加到对应的字段中。