首页Java 在doGet方法中创建两个cake对象并将对象保存在list中，然后请求跳转到ListServlet中，请给出代码示例继续给出上一个问题中ListServlet代码示例

Java 在doGet方法中创建两个cake对象并将对象保存在list中，然后请求跳转到ListServlet中，请给出代码示例继续给出上一个问题中ListServlet代码示例

时间: 2024-05-03 11:20:36 浏览: 159

好的，这是Java代码示例： ```java public class Cake { private int id; private String name; public Cake(int id, String name) { this.id = id; this.name = name; } // getter and setter methods // ... } public class HelloWorld extends HttpServlet { @Override public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { List<Cake> cakes = new ArrayList<Cake>(); cakes.add(new Cake(1, "Chocolate Cake")); cakes.add(new Cake(2, "Cheesecake")); request.setAttribute("cakes", cakes); RequestDispatcher dispatcher = request.getRequestDispatcher("/list"); dispatcher.forward(request, response); } } public class ListServlet extends HttpServlet { @Override public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { List<Cake> cakes = (List<Cake>) request.getAttribute("cakes"); // Output the cakes list PrintWriter out = response.getWriter(); out.println("<html>"); out.println("<body>"); out.println("<h1>List of Cakes</h1>"); out.println("<ul>"); for (Cake cake : cakes) { out.println("<li>" + cake.getName() + "</li>"); } out.println("</ul>"); out.println("</body>"); out.println("</html>"); } } ``` 请注意，这个代码示例仅供参考，可能需要根据您的具体需求进行修改。另外，请确保在使用Java Servlet时遵循安全最佳实践，例如验证用户输入和配置适当的安全性选项。

阅读全文