c语言写：输入一个数n，输出斐波那契数列的第n个，不用函数的递归调用

#include <stdio.h>

int main() {
int n;
scanf("%d", &n);
int a = 0, b = 1, c;
for (int i = 2; i <= n; i++) {
c = a + b;
a = b;
b = c;
}
printf("%d", b);
return 0;
}