简易人机五子棋游戏代码Python

当然可以！以下是一个简易的人机五子棋游戏代码示例（Python）：

import random

# 创建棋盘
def create_board():
    board = [[' ' for _ in range(15)] for _ in range(15)]
    return board

# 打印棋盘
def print_board(board):
    print('   0 1 2 3 4 5 6 7 8 9 10 11 12 13 14')
    for i in range(15):
        print('{:2d}'.format(i), end=' ')
        for j in range(15):
            print(board[i][j], end=' ')
        print()

# 判断是否胜利
def check_win(board, row,, player):
 directions = [(0, 1), (1, 0), (1, 1), (1, -1)]
    for d in directions:
        count = 1
        x, y = row, col
        while count < 5:
            x += d
            y += d
            if x < 0 or x >= 15 or y < 0 or y >= 15 or board[x][y] != player:
                break
            count += 1
        x, y = row, col
        while count < 5:
            x -= d
            y -= d
            if x < 0 or x >= 15 or y < 0 or y >= 15 or board[x][y] != player:
                break
            count += 1
        if count >= 5:
            return True
    return False

# 玩家下棋
def player_move(board):
    while True:
        row = int(input("请输入行号（0-14）："))
        col = int(input("请输入列号（0-14）："))
        if row >= 0 and row < 15 and col >= 0 and col < 15 and board[row][col] == ' ':
            board[row][col] = 'X'
            break
        else:
            print("输入无效，请重新输入！")

# AI下棋
def ai_move(board):
    while True:
        row = random.randint(0, 14)
        col = random.randint(0, 14)
        if board[row][col] == ' ':
            board[row][col] = 'O'
            break

# 游戏主循环
def game_loop():
    board = create_board()
    print_board(board)
    while True:
        player_move(board)
        print_board(board)
        if check_win(board, row, col, 'X'):
            print("玩家胜利！")
            break
        ai_move(board)
        print_board(board)
        if check_win(board, row, col, 'O'):
            print("AI胜利！")
            break

# 启动游戏
game_loop()

希望这个简易的人机五子棋游戏代码对你有帮助！