数据结构构造一个递增有序的正整数链表,实现链表分解为一个奇数表和一个偶数表,之后再将两个链表合并一个递减链表。
时间: 2024-10-25 09:04:15 浏览: 6
88.cpp,设计算法判断单循环链表是否每个结点的值都是偶数
要实现这个功能,首先我们需要设计一个数据结构来存储正整数链表,并将其分为奇数链表和偶数链表。我们可以创建两个单向链表,一个专门用于存储奇数节点,另一个用于存储偶数节点。每个节点包含一个整数值和一个指向下一个节点的指针。
```python
class Node:
def __init__(self, value):
self.value = value
self.next = None
class IncrementalList:
def __init__(self):
self.head = None
self.is_even = False
def add(self, value):
new_node = Node(value)
if not self.head:
self.head = new_node
self.is_even = value % 2 == 0
else:
current = self.head
while current.next and (current.is_even != value % 2 or (value % 2 == 0 and current.value > value) or (value % 2 == 1 and current.value < value)):
current = current.next
new_node.next = current.next
current.next = new_node
# 分解为奇数链表和偶数链表
def split(self):
odd_list, even_list = [], []
current = self.head
while current:
next_even = current.next if current.is_even else None
next_odd = current.next if not current.is_even else None
current.next = None
if current.is_even:
even_list.append(current)
else:
odd_list.append(current)
current = next_even or next_odd
return odd_list, even_list
# 合并为递减链表
@staticmethod
def merge(odd_list, even_list):
odd_tail = None
for node in reversed(odd_list):
if odd_tail:
odd_tail.next = node
else:
odd_head = node
odd_tail = node
even_tail = None
for node in reversed(even_list):
if even_tail:
even_tail.next = node
else:
even_head = node
even_tail = node
merged_list = odd_head
if odd_head and even_head:
odd_tail.next = even_head
tail = even_tail or odd_tail
return merged_list, tail
# 示例
incremental_list = IncrementalList()
incremental_list.add(1)
incremental_list.add(2)
incremental_list.add(3)
incremental_list.add(4)
incremental_list.add(5)
odd_list, even_list = incremental_list.split()
merged_list, merged_tail = IncrementalList.merge(odd_list, even_list)
# 查看结果
current = merged_list
while current:
print(current.value)
current = current.next
```
阅读全文