使用verilog写一个CRC-4的代码,要求输入8位信息位,输出为12位(8信息位+4CRC) ,并写出testbench
时间: 2024-05-07 19:21:00 浏览: 30
以下是CRC-4的Verilog代码和Testbench:
```verilog
module crc4(
input clk,
input reset,
input [7:0] data_in,
output reg [11:0] crc_out
);
reg [7:0] data_reg;
reg [3:0] crc_reg;
always @(posedge clk or negedge reset) begin
if (reset == 0) begin
data_reg <= 8'h00;
crc_reg <= 4'h0;
crc_out <= {data_in, crc_reg};
end
else begin
data_reg <= data_in;
crc_reg <= crc_reg ^ data_reg;
crc_reg <= crc_reg ^ (crc_reg >> 4);
crc_out <= {data_in, crc_reg};
end
end
endmodule
```
```verilog
module crc4_tb();
reg clk, reset;
reg [7:0] data_in;
wire [11:0] crc_out;
crc4 uut (
.clk(clk),
.reset(reset),
.data_in(data_in),
.crc_out(crc_out)
);
initial begin
clk = 0;
reset = 1;
data_in = 8'h00;
#10 reset = 0;
data_in = 8'h1A;
#10;
data_in = 8'h2B;
#10;
data_in = 8'h3C;
#10;
data_in = 8'h4D;
#10;
data_in = 8'h5E;
#10;
data_in = 8'h6F;
#10;
data_in = 8'h70;
#10;
data_in = 8'h81;
#10;
data_in = 8'h92;
#10;
data_in = 8'ha3;
#10;
data_in = 8'hb4;
#10;
data_in = 8'hc5;
#10;
data_in = 8'hd6;
#10;
data_in = 8'he7;
#10;
data_in = 8'hf8;
#10;
$finish;
end
always begin
#5 clk = ~clk;
end
endmodule
```
以上代码实现了CRC-4的计算过程,testbench中给定了一些测试数据用于测试代码的正确性。在testbench中,我们使用了一个时钟信号来模拟实际的时钟信号,因此需要在always块中给时钟信号添加一个5个时间单位的延迟。
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