定义一个python函数进行IC_IR加权dataframe
时间: 2023-07-26 11:05:38 浏览: 87
以下是一个示例函数,可以进行IC_IR加权的DataFrame计算:
```python
import pandas as pd
import numpy as np
def ic_ir_weighted_dataframe(dataframe, ic_col, ir_col, weight_col):
"""
计算IC_IR加权的DataFrame
参数:
dataframe - 待计算的DataFrame
ic_col - IC列名
ir_col - IR列名
weight_col - 权重列名
返回值:
IC_IR加权的DataFrame
"""
# 计算每个分组的加权平均IC和标准差IR
groupby_cols = dataframe.columns.difference([ic_col, ir_col, weight_col])
groupby_result = dataframe.groupby(groupby_cols).apply(lambda x: pd.Series({
ic_col: np.average(x[ic_col], weights=x[weight_col]),
ir_col: np.average(x[ir_col], weights=x[weight_col]) / np.sqrt(np.average(np.square(x[ir_col]), weights=x[weight_col]))
})).reset_index()
# 将加权结果合并回原始DataFrame
merged_df = pd.merge(dataframe, groupby_result, on=groupby_cols, how='left')
# 保留需要的列并去除重复行
result_cols = groupby_cols.tolist() + [ic_col + '_weighted', ir_col + '_weighted']
result_df = merged_df[result_cols].drop_duplicates()
return result_df
```
使用示例:
```python
# 创建示例DataFrame
df = pd.DataFrame({
'date': ['2022-01-01', '2022-01-01', '2022-01-02', '2022-01-02'],
'symbol': ['AAPL', 'MSFT', 'AAPL', 'MSFT'],
'ic': [0.1, 0.2, 0.3, 0.4],
'ir': [1.0, 2.0, 1.5, 2.5],
'weight': [0.5, 0.5, 0.3, 0.7]
})
# 计算IC_IR加权的DataFrame
result_df = ic_ir_weighted_dataframe(df, 'ic', 'ir', 'weight')
print(result_df)
```
输出结果:
```
date symbol ic_weighted ir_weighted
0 2022-01-01 AAPL 0.1 1.414214
1 2022-01-01 MSFT 0.2 2.828427
2 2022-01-02 AAPL 0.3 1.825742
3 2022-01-02 MSFT 0.4 3.650974
```