编写程序求1!+2!+...+10!
时间: 2023-11-09 10:01:52 浏览: 35
可以使用循环来求解1!+2!+...+10!,具体代码如下:
```python
sum = 0
factorial = 1
for i in range(1, 11):
factorial *= i
sum += factorial
print(sum)
```
输出结果为:4037913
相关问题
jav编写程序求1!+2!+...+10!。
以下是 Java 代码实现:
```
public class FactorialSum {
public static void main(String[] args) {
int sum = 0;
for (int i = 1; i <= 10; i++) {
sum += factorial(i);
}
System.out.println("1!+2!+...+10! = " + sum);
}
public static int factorial(int n) {
int result = 1;
for (int i = 1; i <= n; i++) {
result *= i;
}
return result;
}
}
```
输出结果为:1!+2!+...+10! = 4037913
编写程序求1!+2!+3!+..+10!
以下是两种C语言编写程序求1!+2!+3!+..+10!的例子:
引用:
```c
#include <stdio.h>
int main() {
int i = 0;
int result = 1;
int sum = 0;
for (i = 1; i < 11; i++) {
result *= i; // result会保留上一个的阶乘进行相乘
sum += result;
}
printf("1!+2!+3!+……+10!:%d", sum);
return 0;
}
```
引用:
```c
#include <stdio.h>
int main() {
int i = 0;
int j = 0;
int n = 0;
int sum = 0;
int result = 1;
for ( i = 1; i < 11; i++) {
result = 1; // 计算下一个阶乘时,要将result初始化
for (j = 1; j <= i; j++) {
result *= j;
}
sum += result;
}
printf("1!+2!+3!+……+10!:%d", sum);
return 0;
}
```