输入一个四阶方阵，求原矩阵与其转置之和，输出结果。c语言编程

以下是求解原矩阵与其转置之和的C语言代码实现：

#include <stdio.h>

#define N 4

int main() {
    int mat[N][N], sum[N][N];
    int i, j;

    // Input matrix
    printf("Enter a %dx%d matrix:\n", N, N);
    for (i = 0; i < N; i++) {
        for (j = 0; j < N; j++) {
            scanf("%d", &mat[i][j]);
        }
    }

    // Calculate sum of matrix and its transpose
    for (i = 0; i < N; i++) {
        for (j = 0; j < N; j++) {
            sum[i][j] = mat[i][j] + mat[j][i];
        }
    }

    // Print result
    printf("The sum of the matrix and its transpose is:\n");
    for (i = 0; i < N; i++) {
        for (j = 0; j < N; j++) {
            printf("%d ", sum[i][j]);
        }
        printf("\n");
    }

    return 0;
}

输入格式示例：

1 2 3 4
5 6 7 8
9 10 11 12
13 14 15 16

输出结果示例：

The sum of the matrix and its transpose is:
2 7 12 17 
7 12 17 22 
12 17 22 27 
17 22 27 32