利用状态机的VHDL描述方法设计一个序列信号检测器要求检测到0110时输出为1否则输出为0

好的，这是一个编程类的问题，我可以回答。以下是一个利用状态机的VHDL描述方法设计的序列信号检测器的代码：

library ieee;
use ieee.std_logic_1164.all;

entity sequence_detector is
    port (
        clk: in std_logic;
        reset: in std_logic;
        input: in std_logic;
        output: out std_logic
    );
end entity;

architecture behavioral of sequence_detector is
    type state_type is (s0, s1, s2, s3);
    signal current_state, next_state: state_type;
begin
    process (clk, reset)
    begin
        if reset = '1' then
            current_state <= s0;
        elsif rising_edge(clk) then
            current_state <= next_state;
        end if;
    end process;

    process (current_state, input)
    begin
        case current_state is
            when s0 =>
                if input = '0' then
                    next_state <= s0;
                else
                    next_state <= s1;
                end if;
            when s1 =>
                if input = '1' then
                    next_state <= s2;
                else
                    next_state <= s0;
                end if;
            when s2 =>
                if input = '1' then
                    next_state <= s3;
                else
                    next_state <= s0;
                end if;
            when s3 =>
                if input = '0' then
                    output <= '1';
                    next_state <= s0;
                else
                    next_state <= s1;
                end if;
        end case;
    end process;
end architecture;

这个序列信号检测器的功能是检测输入信号中是否包含序列0110，如果包含则输出为1，否则输出为0。