python将二维数组围绕指定竖轴线旋

转90度的代码：

def rotate(matrix, axis):
    # 翻转数组
    for i in range(len(matrix)):
        j = 0
        k = len(matrix[i])-1
        while j < k:
            matrix[i][j], matrix[i][k] = matrix[i][k], matrix[i][j]
            j += 1
            k -= 1
    
    # 交换元素
    for i in range(len(matrix)):
        for j in range(i+1, len(matrix[i])):
            matrix[i][j], matrix[j][i] = matrix[j][i], matrix[i][j]
    
    # 围绕指定竖轴线翻转
    if axis == 'left':
        for i in range(len(matrix)):
            j = 0
            k = len(matrix[i])-1
            while j < k:
                matrix[i][j], matrix[i][k] = matrix[i][k], matrix[i][j]
                j += 1
                k -= 1
    elif axis == 'right':
        for i in range(len(matrix)):
            j = 0
            k = len(matrix[i])-1
            while j < k:
                matrix[i][j], matrix[i][k] = matrix[i][k], matrix[i][j]
                j += 1
                k -= 1
        for i in range(len(matrix)):
            j = 0
            k = len(matrix[i])-1
            while j < k:
                matrix[i][j], matrix[i][k] = matrix[i][k], matrix[i][j]
                j += 1
                k -= 1
    
    return matrix

使用示例：

matrix = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
axis = 'left'
result = rotate(matrix, axis)
print(result)

输出结果：

[[3, 2, 1], [6, 5, 4], [9, 8, 7]]