(1)比赛评分。从10个评委的评分中扣除一个最高分和一个最低分

以下是从10个评委的评分中扣除一个最高分和一个最低分的比赛评分的方法：

#include <stdio.h>

float max(float b[]) {
    float max = b[0];
    for (int i = 1; i < 10; i++) {
        if (b[i] > max) {
            max = b[i];
        }
    }
    return max;}

float min(float b[]) {
    float min = b[0];
    for (int i = 1; i < 10; i++) {
        if (b[i] < min) {
            min = b[i];
        }
    }
    return min;
}

float sum(float b[]) {
    float sum = 0;
    for (int i = 0; i < 10; i++) {
        sum += b[i];
    }
    return sum;}

int main() {
    float score[10];
    float max_score, min_score, total_score;

    printf("请输入10个评委的评分：\n");
    for (int i = 0; i < 10; i++) {
        scanf("%f", &score[i]);
    }

    max_score = max(score);
    min_score = min(score);
    total_score = sum(score) - max_score - min_score;

    printf("去掉一个最高分%.2f和一个最低分%.2f后，选手的得分为%.2f\n", max_score, min_score, total_score / 8);

    return 0;
}