在java2048小游戏不带界面的代码
时间: 2024-08-12 20:09:02 浏览: 30
在Java中创建一个简单的2048游戏(不包含图形用户界面)主要涉及游戏逻辑和数组操作。这里是一个基本的代码框架,展示了如何实现游戏的核心算法:
```java
import java.util.Random;
public class TwentyFortyEight {
private int[][] board;
private int currentScore;
private final int SIZE = 4;
private boolean[][] isFull;
private Random random;
public TwentyFortyEight() {
board = new int[SIZE][SIZE];
currentScore = 0;
isFull = new boolean[SIZE][SIZE];
random = new Random();
initBoard();
}
private void initBoard() {
// 初始化游戏板,一般会随机放置一个2或4
for (int i = 0; i < SIZE; i++) {
for (int j = 0; j < SIZE; j++) {
if (random.nextInt(2) == 1) { // 50%概率放2,50%概率放4
board[i][j] = 2;
} else {
board[i][j] = 4;
}
isFull[i][j] = false;
}
}
}
// 游戏逻辑:合并相邻的相同数字
public void merge(int row, int col) {
if (board[row][col] == 0 || isFull[row][col]) return;
int sum = board[row][col] + board[row][col + 1];
board[row][col] = sum % 2 == 0 ? sum / 2 : sum;
board[row][col + 1] = 0;
isFull[row][col] = true;
isFull[row][col + 1] = true;
currentScore += sum;
}
// 检查游戏是否结束
public boolean isGameOver() {
for (int[] row : board) {
if (!isFull[row]) return false;
}
return true;
}
// 获取当前得分
public int getCurrentScore() {
return currentScore;
}
// 示例:手动执行一次合并
public void playStep() {
int maxScore = Integer.MIN_VALUE;
int maxRow = -1, maxCol = -1;
for (int i = 0; i < SIZE; i++) {
for (int j = 0; j < SIZE - 1; j++) {
if (!isFull[i][j] && board[i][j] == board[i][j + 1]) {
merge(i, j);
if (currentScore > maxScore) {
maxScore = currentScore;
maxRow = i;
maxCol = j;
}
}
}
}
}
// 示例:显示当前状态
public void printBoard() {
for (int[] row : board) {
for (int cell : row) {
System.out.print(cell + " ");
}
System.out.println();
}
}
// 你可以在这个类中添加更多的方法来实现如键盘输入控制、游戏循环等功能
}
```
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