3. 在Python3中通过输入一元二次函数方程组的系数，在屏幕上显示方程式以及两个根 ax2+bx+c=0 (a,b,c)=(1,4,1), (1,2,3),(2,3,5)

在Python3中，你可以创建一个函数来接收一元二次方程的系数，并计算并显示其解。这里是一个简单的例子，展示如何处理给定的三个方程：

import cmath

def quadratic_solver(a, b, c):
    # 计算判别式
    discriminant = (b**2) - (4*a*c)

    roots = []
    if discriminant > 0:
        root1 = (-b + cmath.sqrt(discriminant)) / (2 * a)
        root2 = (-b - cmath.sqrt(discriminant)) / (2 * a)
        roots.append(root1.real)
        roots.append(root2.real)
    elif discriminant == 0:
        root = -b / (2 * a)
        roots.append(root)
    else:
        real_part = -b / (2 * a)
        imaginary_part = cmath.sqrt(-discriminant) / (2 * a)
        roots.append(real_part)
        roots.append(imaginary_part)

    print(f"对于方程 {a}x^2 + {b}x + {c} = 0 的解是:")
    for i, root in enumerate(roots):
        print(f"根{i+1}: {root}")

# 给定的方程系数
coefficients_list = [(1, 4, 1), (1, 2, 3), (2, 3, 5)]

for coefficients in coefficients_list:
    quadratic_solver(*coefficients)