--------- beginning of system 和 --------- beginning of main 区别

时间: 2023-09-26 07:07:02 浏览: 126
"--------- beginning of system" 和 "--------- beginning of main" 是在代码文件中的两个标记,用于区分系统代码和主要代码的不同部分。 "--------- beginning of system" 标记通常用于指示系统级别的代码,例如导入库、全局变量的定义、配置设置等。这部分代码是整个程序的基础,用于提供必要的功能和资源。 而 "--------- beginning of main" 标记通常用于指示主要的业务逻辑代码,例如函数的定义、程序的入口点等。这部分代码是程序的核心,用于执行实际的任务和操作。 通过使用这样的标记,开发人员可以更清晰地区分系统级别代码和主要代码,使代码结构更加清晰和易于维护。
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130|console:/ # logcat -s alogd --------- beginning of kernel --------- beginning of system --------- beginning of main

根据提供的引用内容,您想了解如何使用logcat命令查看Android设备的日志。logcat命令用于查看系统日志和应用程序日志。以下是使用logcat命令查看Android设备日志的示例: ```shell logcat -s alogd ``` 这个命令将过滤并显示与"alogd"相关的日志信息。请注意,您需要在Android设备上运行此命令,并且您的设备必须具有root权限才能访问系统日志。

用java语言实现实现银行家算法、进程调度过程的模拟、读者-写者问题的写者优先算法。

银行家算法的Java实现: ```java import java.util.Scanner; public class BankersAlgorithm { public static void main(String[] args) { Scanner sc = new Scanner(System.in); System.out.print("Enter the number of processes: "); int n = sc.nextInt(); System.out.print("Enter the number of resources: "); int m = sc.nextInt(); int[][] max = new int[n][m]; int[][] allocation = new int[n][m]; int[][] need = new int[n][m]; int[] available = new int[m]; System.out.println("Enter the maximum matrix:"); for (int i = 0; i < n; i++) { for (int j = 0; j < m; j++) { max[i][j] = sc.nextInt(); } } System.out.println("Enter the allocation matrix:"); for (int i = 0; i < n; i++) { for (int j = 0; j < m; j++) { allocation[i][j] = sc.nextInt(); } } System.out.println("Enter the available matrix:"); for (int i = 0; i < m; i++) { available[i] = sc.nextInt(); } // Calculate the need matrix for (int i = 0; i < n; i++) { for (int j = 0; j < m; j++) { need[i][j] = max[i][j] - allocation[i][j]; } } // Check if the system is in a safe state if (isSafe(n, m, allocation, need, available)) { System.out.println("The system is in a safe state."); } else { System.out.println("The system is not in a safe state."); } } public static boolean isSafe(int n, int m, int[][] allocation, int[][] need, int[] available) { boolean[] visited = new boolean[n]; int[] work = new int[m]; // Initialize the work matrix for (int i = 0; i < m; i++) { work[i] = available[i]; } // Initialize the visited matrix for (int i = 0; i < n; i++) { visited[i] = false; } // Find an unvisited process that can be completed for (int i = 0; i < n; i++) { if (!visited[i] && canComplete(i, m, allocation, need, work)) { visited[i] = true; // Add the allocated resources to the work matrix for (int j = 0; j < m; j++) { work[j] += allocation[i][j]; } // Start over from the beginning of the process list i = -1; } } // Check if all processes have been visited for (int i = 0; i < n; i++) { if (!visited[i]) { return false; } } return true; } public static boolean canComplete(int i, int m, int[][] allocation, int[][] need, int[] work) { for (int j = 0; j < m; j++) { if (need[i][j] > work[j]) { return false; } } return true; } } ``` 进程调度过程的模拟的Java实现: ```java import java.util.Arrays; import java.util.Scanner; public class ProcessScheduling { public static void main(String[] args) { Scanner sc = new Scanner(System.in); System.out.print("Enter the number of processes: "); int n = sc.nextInt(); int[] arrivalTime = new int[n]; int[] burstTime = new int[n]; int[] completionTime = new int[n]; int[] waitingTime = new int[n]; int[] turnaroundTime = new int[n]; int[] remainingTime = new int[n]; for (int i = 0; i < n; i++) { System.out.print("Enter the arrival time of process " + (i + 1) + ": "); arrivalTime[i] = sc.nextInt(); System.out.print("Enter the burst time of process " + (i + 1) + ": "); burstTime[i] = sc.nextInt(); remainingTime[i] = burstTime[i]; } // Sort the processes by arrival time sortProcesses(n, arrivalTime, burstTime); int time = 0; int completed = 0; while (completed < n) { int i = getNextProcess(n, arrivalTime, remainingTime, time); if (i == -1) { time++; } else { remainingTime[i]--; if (remainingTime[i] == 0) { completionTime[i] = time + 1; waitingTime[i] = completionTime[i] - arrivalTime[i] - burstTime[i]; turnaroundTime[i] = completionTime[i] - arrivalTime[i]; completed++; } time++; } } double avgWaitingTime = getAverage(waitingTime); double avgTurnaroundTime = getAverage(turnaroundTime); System.out.println("Process\tArrival Time\tBurst Time\tCompletion Time\tWaiting Time\tTurnaround Time"); for (int i = 0; i < n; i++) { System.out.println((i + 1) + "\t\t" + arrivalTime[i] + "\t\t" + burstTime[i] + "\t\t" + completionTime[i] + "\t\t" + waitingTime[i] + "\t\t" + turnaroundTime[i]); } System.out.println("Average waiting time: " + avgWaitingTime); System.out.println("Average turnaround time: " + avgTurnaroundTime); } public static void sortProcesses(int n, int[] arrivalTime, int[] burstTime) { for (int i = 0; i < n; i++) { for (int j = i + 1; j < n; j++) { if (arrivalTime[i] > arrivalTime[j]) { swap(arrivalTime, i, j); swap(burstTime, i, j); } } } } public static int getNextProcess(int n, int[] arrivalTime, int[] remainingTime, int time) { int minRemainingTime = Integer.MAX_VALUE; int nextProcess = -1; for (int i = 0; i < n; i++) { if (arrivalTime[i] <= time && remainingTime[i] > 0 && remainingTime[i] < minRemainingTime) { minRemainingTime = remainingTime[i]; nextProcess = i; } } return nextProcess; } public static double getAverage(int[] arr) { double sum = 0; for (int i = 0; i < arr.length; i++) { sum += arr[i]; } return sum / arr.length; } public static void swap(int[] arr, int i, int j) { int temp = arr[i]; arr[i] = arr[j]; arr[j] = temp; } } ``` 读者-写者问题的写者优先算法的Java实现: ```java import java.util.concurrent.Semaphore; public class ReaderWriter { private static int readCount = 0; private static Semaphore rMutex = new Semaphore(1); private static Semaphore wMutex = new Semaphore(1); private static Semaphore resource = new Semaphore(1); public static void main(String[] args) { Thread[] readers = new Thread[3]; Thread[] writers = new Thread[2]; for (int i = 0; i < readers.length; i++) { readers[i] = new Thread(new Reader(i)); readers[i].start(); } for (int i = 0; i < writers.length; i++) { writers[i] = new Thread(new Writer(i)); writers[i].start(); } } static class Reader implements Runnable { private int id; public Reader(int id) { this.id = id; } public void run() { while (true) { try { // Acquire the rMutex semaphore to ensure mutual exclusion rMutex.acquire(); // Increment the read count readCount++; // If this is the first reader, acquire the resource semaphore to prevent writers from accessing the resource if (readCount == 1) { resource.acquire(); } // Release the rMutex semaphore to allow other readers to access the read count rMutex.release(); // Read the resource System.out.println("Reader " + id + " is reading the resource."); // Acquire the rMutex semaphore to ensure mutual exclusion rMutex.acquire(); // Decrement the read count readCount--; // If this is the last reader, release the resource semaphore to allow writers to access the resource if (readCount == 0) { resource.release(); } // Release the rMutex semaphore to allow other readers to access the read count rMutex.release(); // Sleep for a random amount of time Thread.sleep((long)(Math.random() * 100)); } catch (InterruptedException e) { e.printStackTrace(); } } } } static class Writer implements Runnable { private int id; public Writer(int id) { this.id = id; } public void run() { while (true) { try { // Acquire the wMutex semaphore to ensure mutual exclusion wMutex.acquire(); // Acquire the resource semaphore to prevent other writers and readers from accessing the resource resource.acquire(); // Write to the resource System.out.println("Writer " + id + " is writing to the resource."); // Release the resource semaphore to allow other writers and readers to access the resource resource.release(); // Release the wMutex semaphore to allow other writers to access the resource wMutex.release(); // Sleep for a random amount of time Thread.sleep((long)(Math.random() * 100)); } catch (InterruptedException e) { e.printStackTrace(); } } } } } ```

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Write java code: Copy the files, small_weapons.txt, and large_weapons.txt from the assignment folder on Blackboard and save them to your folder. For testing purposes, you should use the small file. Use the large file when you think the application works correctly. To see what is in the files use a text editor. Nilesh is currently enjoying the action RPG game Torchlight 2 which is an awesome game and totally blows Auction House Simulator 3, oh sorry, that should be Diablo 3, out of the water. He has got a file containing info on some of the unique weapons in the game. The transaction file contains the following information: Weapon Name (string) Weapon Type (string) Damage (int) Weapon Speed (double) … To tell if one weapon is better than another you need to know the Damage Per Second (DPS) the weapon does, since weapons have a different attack speed. DPS is calculated by taking the damage value and dividing it by the attack speed.a) You will write a program that will allow Nilesh to load the file and display the weapon info and DPS of every weapon in the input file. When the user chooses to open a weapon file, they are required to type in the filename. It will then read the 4 values about a particular weapon and then display the 4 values to the console window on one line neatly padded along with the DPS of the weapon. This is repeated until the end of the file. b) Modify your code from a) so that the weapon information written to the console window is also written to a text file. The user should be able to specify the name of the file. Add a header to the beginning of the file which has column headers for each column. At the end of the text file display the total number of weapons in the file. c) Document your code appropriately and add your name and id number as comments at the top of your code. Please also submit this text file you have created. Enter the file you want to search end with .txt: large_weapons.txt 1 Blackfang Bludgeon Great Hammer 489 1.44 339.58333333333337 2 Bones 2 Boneshredder Great Axe 256 0.84 304.76190476190476 3 Comet's Tail Great Sword 872 1.2 726.6666666666667 4 Decapitator Great Sword 188 1.08 174.07407407407408 5 Demolisher Great Hammer 887 1.32 671.9696969696969

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