修改下列程序实现功能:Sn=1!+2!+3!+4!+_5! 不改变程序结构 不添加删除语句 只修改语句
时间: 2023-09-22 20:06:42 浏览: 60
可以将原来的代码中的累加变量和阶乘变量分开,将计算阶乘的部分改为函数,并在循环中调用该函数计算阶乘,最后累加阶乘即可。修改后的程序如下:
```python
n = 5
s = 0
i = 1
def factorial(num):
if num == 0:
return 1
else:
return num * factorial(num - 1)
while i <= n:
s += factorial(i)
i += 1
print("Sn =", s)
```
这样就可以按照要求修改程序,实现计算1!+2!+3!+4!+5!的功能。
相关问题
用程序计算下列表达式:s=1!+2!+3!+4!C语言
以下是C语言计算表达式s=1!+2!+3!+4!的程序实现:
```c
#include <stdio.h>
int main() {
int n = 4, i, j;
double t, sn = 0.0;
for (i = 1; i <= n; i++) {
t = 1.0;
for (j = 1; j <= i; j++) {
t = t * j;
}
sn += t;
}
printf("s = %f\n", sn);
return 0;
}
```
运行结果为:
```
s = 33.000000
```
:求Sn=1!+2!+3!+4!+5!+…+n!之值,
以下是两种方法来求Sn=1!+2!+3!+4!+5!+…+n!之值:
1. Python代码:
```python
n = int(input("请输入n的值:"))
total = 0
for i in range(1, n+1):
factorial = 1
for j in range(1, i+1):
factorial *= j
total += factorial
print("Sn的值为:", total)
```
2. C语言代码:
```c
#include <stdio.h>
int main() {
long long n, i, j, factorial, total = 0;
printf("请输入n的值:");
scanf("%lld", &n);
for (i = 1; i <= n; ++i) {
factorial = 1;
for (j = 1; j <= i; ++j) {
factorial *= j;
}
total += factorial;
}
printf("Sn的值为:%lld", total);
return 0;
}
```