使用python写一个推箱子游戏的函数

好的，下面是一个简单的推箱子游戏的 Python 函数实现：

def push_box_game(map):
    ROWS = len(map)
    COLS = len(map[0])
    player_pos = None
    boxes = []
    goals = []
    for r in range(ROWS):
        for c in range(COLS):
            if map[r][c] == "P":
                player_pos = (r, c)
                map[r][c] = " "
            elif map[r][c] == "B":
                boxes.append((r, c))
                map[r][c] = " "
            elif map[r][c] == "G":
                goals.append((r, c))
                map[r][c] = " "
    
    def check_win():
        for box in boxes:
            if box not in goals:
                return False
        return True
    
    def move_player(dx, dy):
        nonlocal player_pos
        x, y = player_pos
        new_x, new_y = x + dx, y + dy
        if not (0 <= new_x < ROWS and 0 <= new_y < COLS):
            return False
        if map[new_x][new_y] == " ":
            player_pos = (new_x, new_y)
            return True
        for box in boxes:
            bx, by = box
            if bx == new_x and by == new_y:
                new_bx, new_by = bx + dx, by + dy
                if not (0 <= new_bx < ROWS and 0 <= new_by < COLS):
                    return False
                if map[new_bx][new_by] == " " and (new_bx, new_by) not in boxes:
                    box = (new_bx, new_by)
                    boxes.remove((bx, by))
                    boxes.append(box)
                    player_pos = (new_x, new_y)
                    return True
        return False           
    
    while not check_win():
        print_map(map, player_pos, boxes, goals)
        move = input("Enter move (u/d/l/r): ")
        dx, dy = 0, 0
        if move == "u":
            dx, dy = -1, 0
        elif move == "d":
            dx, dy = 1, 0
        elif move == "l":
            dx, dy = 0, -1
        elif move == "r":
            dx, dy = 0, 1
        if dx != 0 or dy != 0:
            if move_player(dx, dy):
                clear_output()
            else:
                print("Invalid move!")
                time.sleep(1)
                clear_output()
    print_map(map, player_pos, boxes, goals)
    print("You won!")
    
def print_map(map, player_pos, boxes, goals):
    ROWS = len(map)
    COLS = len(map[0])
    for r in range(ROWS):
        for c in range(COLS):
            if (r, c) == player_pos:
                print("P", end="")
            elif (r, c) in boxes:
                print("B", end="")
            elif (r, c) in goals:
                print("G", end="")
            else:
                print(map[r][c], end="")
        print()
        
map = [
    ["#", "#", "#", "#", "#", "#", "#", "#", "#"],
    ["#", " ", " ", " ", "B", " ", " ", " ", "#"],
    ["#", " ", " ", " ", " ", " ", " ", " ", "#"],
    ["#", " ", " ", " ", " ", " ", " ", " ", "#"],
    ["#", " ", " ", " ", " ", " ", " ", " ", "#"],
    ["#", " ", " ", " ", " ", " ", " ", " ", "#"],
    ["#", " ", " ", " ", " ", " ", "G", " ", "#"],
    ["#", " ", " ", " ", " ", " ", " ", " ", "#"],
    ["#", "#", "#", "#", "#", "#", "#", "#", "#"]
]

push_box_game(map)

这个函数接受一个地图作为参数，地图是一个二维数组，其中 # 表示墙，空格表示空格子，P 表示玩家，B 表示箱子，G 表示目标点。

函数使用了 Python 的闭包来实现内部函数的访问和修改外部变量。函数中的 `check_win` 函数用于判断游戏是否胜利，`move_player` 函数用于移动玩家和箱子，`print_map` 函数用于输出当前地图状态。函数执行时会进入一个循环，不断等待玩家输入移动指令，然后根据输入来移动玩家和箱子。当所有的箱子都被推到目标点上时，函数会输出胜利信息并结束游戏。

注意：这个函数使用了 `clear_output` 和 `time.sleep` 函数来清除屏幕和暂停一段时间，这些函数只在 Jupyter Notebook 等交互式环境中可用，如果在命令行中运行需要另外实现清屏和暂停功能。