mu_s = -1572.5; sigma_s = sqrt(60.2);修改这段代码为服从均匀分布,最大值为1800.6,最小值为1400.9
时间: 2024-02-17 20:00:53 浏览: 21
将这段代码修改为服从均匀分布,最大值为1800.6,最小值为1400.9的代码如下所示:
```
s = unifrnd(1400.9, 1800.6); % 生成一个在 [1400.9, 1800.6] 范围内均匀分布的随机数
```
其中,`mu_s` 和 `sigma_s` 分别代表原来代码中的正态分布的均值和标准差,由于均匀分布没有均值和标准差的概念,因此直接使用 `unifrnd()` 函数生成一个在指定范围内均匀分布的随机数即可。
相关问题
% 设置模拟参数 N = 10000; mu_p = 198900; sigma_p = sqrt(4500.2); mu_f = 120050.28; sigma_f = sqrt(3900.6); mu_r =30710; sigma_r = sqrt(892.6); mu_s = -1572.5; sigma_s = sqrt(60.2); % 生成随机样本 p_cost = normrnd(mu_p, sigma_p, [N, 1]); f_cost = normrnd(mu_f, sigma_f, [N, 1]); r_cost = normrnd(mu_r, sigma_r, [N, 1]); s_cost = normrnd(mu_s, sigma_s, [N, 1]); % 计算总成本 total_cost = p_cost + f_cost + r_cost + s_cost; % 绘制总成本直方图 histogram(total_cost, 'Normalization', 'pdf'); xlabel('Total Cost (Millions of Yuan)'); ylabel('Probability Density'); % 输出统计信息 fprintf('Mean Total Cost: %.2f (Millions of Yuan)\n', mean(total_cost)); fprintf('Standard Deviation of Total Cost: %.2f (Millions of Yuan)\n', std(total_cost));帮我修改输出结果横坐标的跨度
可以使用 `xlim` 函数修改输出结果横坐标的跨度。例如,将横坐标范围设置为 $[50, 350]$,可以在代码最后添加以下语句:
```matlab
xlim([50, 350]);
```
修改后的完整代码如下:
```matlab
% 设置模拟参数
N = 10000;
mu_p = 198900;
sigma_p = sqrt(4500.2);
mu_f = 120050.28;
sigma_f = sqrt(3900.6);
mu_r = 30710;
sigma_r = sqrt(892.6);
mu_s = -1572.5;
sigma_s = sqrt(60.2);
% 生成随机样本
p_cost = normrnd(mu_p, sigma_p, [N, 1]);
f_cost = normrnd(mu_f, sigma_f, [N, 1]);
r_cost = normrnd(mu_r, sigma_r, [N, 1]);
s_cost = normrnd(mu_s, sigma_s, [N, 1]);
% 计算总成本
total_cost = p_cost + f_cost + r_cost + s_cost;
% 绘制总成本直方图
histogram(total_cost, 'Normalization', 'pdf');
xlabel('Total Cost (Millions of Yuan)');
ylabel('Probability Density');
xlim([50, 350]);
% 输出统计信息
fprintf('Mean Total Cost: %.2f (Millions of Yuan)\n', mean(total_cost));
fprintf('Standard Deviation of Total Cost: %.2f (Millions of Yuan)\n', std(total_cost));
```
完善代码:import math class Triangle: def __init__(self, a, b, c): self.__a = a self.__b = b self.__c = c def get_area(self): h = (self.__a+self.__b+self.__c)/2 s = math.sqrt(h*(h-self.__a)*(h-self.__b)*(h-self.__c)) print(f'三角形的面积:{s}') tri = Triangle(3, 4, 5)
代码已经很完整了,只需要添加一行代码来调用 `get_area()` 方法即可计算三角形的面积,如下所示:
```
tri.get_area()
```
完整代码如下:
```python
import math
class Triangle:
def __init__(self, a, b, c):
self.__a = a
self.__b = b
self.__c = c
def get_area(self):
h = (self.__a+self.__b+self.__c)/2
s = math.sqrt(h*(h-self.__a)*(h-self.__b)*(h-self.__c))
print(f'三角形的面积:{s}')
tri = Triangle(3, 4, 5)
tri.get_area()
```
输出结果为:
```
三角形的面积:6.0
```