求1+2!+3!+...+n!的和.
时间: 2023-11-24 21:53:18 浏览: 26
以下是Python计算1+2!+3!+...+n!的和的方法:
```python
def factorial(n):
if n == 0:
return 1
else:
return n * factorial(n-1)
def sum_factorial(n):
sum = 0
for i in range(1, n+1):
sum += factorial(i)
return sum
n = 5
print("1+2!+3!+...+n!的和为:", sum_factorial(n)) # 输出:1+2!+3!+4!+5!=153
```
相关问题
python求1+2!+3!+...+N!的和
以下是两种Python求1+2!+3!+...+N!的和的方法:
1.使用for循环计算阶乘和
```python
n = int(input("请输入一个正整数:"))
sum = 0
factorial = 1
for i in range(1, n+1):
factorial *= i
sum += factorial
print("1+2!+3!+...+{}!的和为:{}".format(n, sum))
```
2.使用递归函数调用阶乘方法求和
```python
def jie(n):
if n == 1:
return 1
else:
return n*jie(n-1)
n = int(input("请输入一个正整数:"))
sum = 0
if n < 1 or n > 40:
print("请重新输入数据")
else:
for i in range(1, n+1):
sum += jie(i)
print("1+2!+3!+...+{}!的和为:{}".format(n, sum))
```
Python求1+2!+3!+...+n!的和.
以下是两种Python求1+2!+3!+...+n!的和的方法:
1.使用for循环计算阶乘和
```python
n = int(input("请输入一个正整数:"))
sum = 0
factorial = 1
for i in range(1, n+1):
factorial *= i
sum += factorial
print("1+2!+3!+...+n!的和为:", sum)
```
2.使用递归函数调用阶乘方法求和
```python
def jie(n):
if n == 1:
return 1
else:
return n*jie(n-1)
n = int(input("请输入一个正整数:"))
sum = 0
if n < 1 or n > 40:
print("请重新输入数据")
else:
for i in range(1, n+1):
sum += jie(i)
print("1+2!+3!+...+n!的和为:", sum)
```