用Python编写程序,计算s=1!+2!+…+n!
时间: 2023-11-15 09:00:33 浏览: 48
可以使用Python的循环和递归两种方式来计算s=1!+2!+…+n!。
1. 循环方式:
```python
def factorial(n):
result = 1
for i in range(1, n+1):
result *= i
return result
def sum_factorial(n):
s = 0
for i in range(1, n+1):
s += factorial(i)
return s
```
2. 递归方式:
```python
def factorial(n):
if n == 0:
return 1
else:
return n * factorial(n-1)
def sum_factorial(n):
if n == 0:
return 0
else:
return sum_factorial(n-1) + factorial(n)
```
其中,factorial函数用于计算n的阶乘,sum_factorial函数用于计算s=1!+2!+…+n!。
相关问题
编写程序,计算s=1!+2!+3!+…+n!
可以使用循环和递归两种方式来计算s=1!+2!+3!+…+n!,下面分别给出两种实现方式的代码:
1. 循环实现:
```python
def factorial(n):
result = 1
for i in range(1, n+1):
result *= i
return result
def sum_of_factorials(n):
s = 0
for i in range(1, n+1):
s += factorial(i)
return s
```
2. 递归实现:
```python
def factorial(n):
if n == 0:
return 1
else:
return n * factorial(n-1)
def sum_of_factorials(n):
if n == 0:
return 1
else:
return factorial(n) + sum_of_factorials(n-1)
```
编写程序,计算s=1!+2!+3!…+n!
可以使用循环和递归两种方式来计算s=1!+2!+3!…+n!,下面分别给出两种实现方式的代码:
1. 循环实现方式:
```python
def factorial(n):
result = 1
for i in range(1, n+1):
result *= i
return result
def sum_factorial(n):
s = 0
for i in range(1, n+1):
s += factorial(i)
return s
```
2. 递归实现方式:
```python
def factorial(n):
if n == 1:
return 1
else:
return n * factorial(n-1)
def sum_factorial(n):
s = 0
for i in range(1, n+1):
s += factorial(i)
return s
```