python opencv按照比例对原图像缩放

要按照比例对原图像进行缩放，可以使用Python和OpenCV库来实现。以下是一个代码示例：

import cv2

def resize_image_proportionally(image_path, scale):
    # 读取图片
    img = cv2.imread(image_path)

    # 获取原始分辨率
    height, width = img.shape[:2]

    # 按比例缩放
    new_height = int(height * scale)
    new_width = int(width * scale)
    resized_img = cv2.resize(img, (new_width, new_height))

    # 输出结果
    cv2.imshow('Resized Image', resized_img)
    cv2.waitKey(0)
    cv2.destroyAllWindows()

# 调用函数进行缩放
image_path = 'path_to_image.jpg'  # 替换为实际的图像路径
scale = 0.5  # 替换为想要缩放的比例
resize_image_proportionally(image_path, scale)

这段代码会按照指定的比例对原图像进行缩放，并在窗口中显示缩放后的图像。你可以替换`image_path`变量为你想要缩放的图像的路径，以及替换`scale`变量为你想要的缩放比例。<span class="em">1</span><span class="em">2</span><span class="em">3</span>
#### 引用[.reference_title]
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