一年365天(假定第一天为星期天),一周5个工作日,如果每个工作日都很努力,能力值可 以提高1%,仅在周末放任一下,能力值每天下降1%.试编一程序,计算一年后的最终效果python
时间: 2024-10-18 18:18:16 浏览: 2
为了编写这样一个Python程序,我们首先需要设置几个变量,如初始能力值、每周的工作天数、每天的能力变化等。然后我们可以创建一个函数来模拟一年的行为。以下是简单的步骤和代码示例:
```python
def calculate_ability(initial_ability, work_days_per_week, increase_percentage, decrease_percentage):
weeks_in_year = 52 # 假设一年有52周,忽略闰年
ability_change = (increase_percentage - decrease_percentage) * work_days_per_week
def simulate_week(end_of_previous_week):
non_work_days = 2 # 每周两天休息
total_days = end_of_previous_week + non_work_days
return initial_ability * ((1 + increase_percentage) ** (work_days_per_week)) * ((1 - decrease_percentage) ** non_work_days) if total_days <= 7 else simulate_week(total_days)
start_of_year = 0
final_ability = simulate_week(start_of_year)
return final_ability, final_ability / initial_ability - 1 # 返回最后的能力值和提升比例
# 示例参数
initial_ability = 100 # 初始能力值假设为100%
work_days_per_week = 5
increase_percentage = 0.01
decrease_percentage = 0.01
final_ability, improvement_rate = calculate_ability(initial_ability, work_days_per_week, increase_percentage, decrease_percentage)
print(f"一年后的能力值:{final_ability:.2f}")
print(f"能力提升百分比:{improvement_rate*100}%")
#
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