能否提供一个详细的六子棋游戏程序代码示例,包括所有必要的函数和规则实现?
时间: 2024-10-21 09:12:57 浏览: 32
由于六子棋规则相对简单,这里我将给出一个非常基础的Python程序框架,使用了Minimax算法作为核心。完整的游戏代码会涉及到更多的细节,例如用户界面、图形化显示棋盘、错误检查等,但这个基础版本可以帮助理解算法的核心逻辑。
```python
import numpy as np
# 定义棋盘大小
BOARD_SIZE = 15
# 棋盘表示
class Board:
def __init__(self):
self.board = np.zeros((BOARD_SIZE, BOARD_SIZE), dtype=int)
# 根据坐标落子
def place_stone(self, player, row, col):
self.board[row][col] = player
# 判断是否有连线获胜
def check_win(self, player):
win_conditions = [(0, 1, 2), (3, 4, 5), (6, 7, 8), (9, 10, 11),
(12, 13, 14), (0, 3, 6), (1, 4, 7), (2, 5, 8),
(0, 12, 15), (1, 13, 14)]
for condition in win_conditions:
if all(self.board[row + c] == player for c in condition):
return True
return False
# Minimax函数
def minimax(board, player, max_depth=5):
if board.check_win(player):
return -1 if player == 1 else 1 # 胜利得正分,失败得负分
elif not any(row.any() for row in board.board): # 平局
return 0
elif max_depth == 0 or np.all(board.board == 0): # 深度达到或棋盘为空
return evaluate(board)
# 假设是最大化得分
if player == 1:
value = -np.inf
for next_row, next_col in get_valid_moves(board):
new_board = Board.from_matrix(board.board.copy())
new_board.place_stone(1, next_row, next_col)
value = max(value, minimax(new_board, 2, max_depth - 1))
return value
# 假设是最大化得分,对手是2
else:
value = np.inf
for next_row, next_col in get_valid_moves(board):
new_board = Board.from_matrix(board.board.copy())
new_board.place_stone(2, next_row, next_col)
value = min(value, minimax(new_board, 1, max_depth - 1))
return value
# 得到合法移动
def get_valid_moves(board):
valid_moves = []
for row in range(BOARD_SIZE):
for col in range(BOARD_SIZE):
if board.board[row][col] == 0:
valid_moves.append((row, col))
return valid_moves
# 评价函数
def evaluate(board):
# 实际上需要根据实际规则进行评估,这里简化为均匀分布
return sum(sum(board.board))
# 主游戏循环
def play():
game_board = Board()
while not game_board.check_win(1) and not game_board.check_win(2):
print(game_board)
player = 1 if game_board.board[-1][-1] == 0 else 2
row, col = input(f"Player {player}, enter your move (row, col): ").split(',')
game_board.place_stone(player, int(row), int(col))
winner = minimax(game_board, player)
if winner != 0:
print(f"Player {winner+1} wins!")
break
play()
```
在这个代码中,玩家轮流输入他们的行和列,然后Minimax函数会决定下一个最好的动作。请注意,此代码只是一个简化的示例,实际应用中你可能还需要添加更多的细节和优化。
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