使用函数实现求下列值 1！+1！+2！+1！+2！+3！+……+1！+2！+3！+……+n！用C语言嵌套jck

以下是使用函数实现求下列值的C语言代码：

#include <stdio.h>
#include <stdlib.h>

int Factor(int n) //计算n的阶乘
{
    int result = 1;
    for (int i = 1; i <= n; i += 1) {
        result *= i;
    }
    return result;
}
int FactorSum(int n) //计算1!+2!+3!+...+n!的和
{
    int sum = 0;
    for (int i = 1; i <= n; i += 1) {
        for (int j = 1; j <= i; j += 1) {
            sum += Factor(j);
        }
    }
    return sum;
}

int main()
{
    int n = 5; //n为5
    int result = FactorSum(n);
    printf("result = %d\n", result);
    system("pause");
    return 0;
}