分别用3-8译码器和4选1的数据选择器分别实现如下函数: F=AB'C'+A'C'+BC
时间: 2023-06-11 22:06:12 浏览: 120
使用3-8译码器实现:
首先,可以将函数 F 转换为其对应的卡诺图:
```
AB'
C' 00 01 11 10
A' +---+---+---+---+
| 0 | 1 | 0 | 0 |
B +---+---+---+---+
C | 0 | 0 | 1 | 0 |
+---+---+---+---+
```
可以看到,卡诺图的第一列和第三列都只有一个 1,因此可以使用一个 3-8 译码器来实现。
将 A, B, C' 分别连接到 3-8 译码器的 A, B, C 输入端,将 1, 2, 4 输出分别连接到 AND 门的输入端,将 3 输出连接到 NOT 门的输入端,将 AND 门和 NOT 门的输出连接到 OR 门的输入端,得到如下电路图:
```
+---+ +---+ +---+ +---+
A -----| | | | | | | |----- F
| 3 | | 2 | | 1 | | 0 |
B -----| | | | | | | |
+---+ +---+ +---+ +---+
| | | |
| | | |
| | | |
+---+ +---+ +---+ +---+
C' ----|NOT|-----|AND|-----|AND|-----|OR |
| | | | | | | |
+---+ +---+ +---+ +---+
```
使用 4 选 1 的数据选择器实现:
可以将函数 F 表达为:
```
F = AB'C' + A'C'BC
```
可以使用一个 4 选 1 的数据选择器来实现。
将 A, B, C' 分别连接到 4 个 AND 门的输入端,将 A', B, C' 分别连接到 4 个 AND 门和 1 个 NOT 门的输入端,将 A, B, C 分别连接到 4 个 AND 门和 1 个 NOT 门的输入端,将 4 个 AND 门的输出分别连接到 4 个数据输入端,将 1, 2, 3, 4 分别连接到地址输入端,将 数据选择器的输出与 OR 门的输入端相连,得到如下电路图:
```
+---+ +---+ +---+ +---+ +---+
A -----| | | | | | | | | |-----+
| | | | | | | | | | |
+---+ +---+ +---+ +---+ +---+ |
| | | | | |
| | | | | |
| | | | | |
+---+ +---+ +---+ +---+ +---+ |
A' ----|NOT|-----| | | | | | | | |
| | | | | | | | | | |
+---+ +---+ +---+ +---+ +---+ |
| | | | | |
B -----| |-----| | | | | | | | |
| | | | | | | | | | |
+---+ +---+ +---+ +---+ +---+ |
| | | | | |
C' ----| |-----| | | | | | | | |
| | | | | | | | | | |
+---+ +---+ +---+ +---+ +---+ |
| | | | | |
B -----| | +---+ +---+ +---+ +---+ |
| | 1 2 3 4 | |
+---+ AND AND AND AND | |
| | | | | |
C -----| |-----| |-----| |-----| |-----|SEL |
| | | | | | | | | |
+---+ +---+ +---+ +---+ +---+ |
| | | | | | |
| | | | | | |
| | | | | | |
+---+ +---+ +---+ +---+ +---+ | |
F -----|OR |-----| |-----| |-----| |-----|OUT|--+
| | | | | | | | | |
+---+ +---+ +---+ +---+ +----+
```
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