verilog语言四层电梯
时间: 2023-08-28 20:06:18 浏览: 17
以下是一个简单的四层电梯的verilog代码实现:
```verilog
module elevator(
input clk,
input reset,
input [1:0] floor_req,
input up,
input down,
output [1:0] current_floor
);
reg [1:0] current_floor;
reg [1:0] next_floor;
reg [1:0] floor_mask;
reg up_pressed;
reg down_pressed;
parameter idle = 2'b00;
parameter moving_up = 2'b01;
parameter moving_down = 2'b10;
//设置当前楼层为1楼
initial current_floor = 2'b01;
//设置电梯状态为 idle
reg [1:0] state = idle;
always @(posedge clk) begin
if (reset) begin
// 重置电梯状态为 idle
state <= idle;
floor_mask <= 2'b00;
end else begin
case (state)
idle: begin
if (floor_req != 2'b00) begin
if (floor_req > current_floor) begin
next_floor <= floor_req;
state <= moving_up;
end else if (floor_req < current_floor) begin
next_floor <= floor_req;
state <= moving_down;
end
end
end
moving_up: begin
// 电梯上升
current_floor <= current_floor + 1;
// 到达目标楼层
if (current_floor == next_floor) begin
// 打开电梯门,并清除该楼层的请求
floor_mask <= floor_mask & ~(1 << (current_floor - 1));
// 如果还有请求,继续移动
if (floor_mask != 2'b00) begin
next_floor <= $ffs(floor_mask) - 1;
end else begin
state <= idle;
end
end
end
moving_down: begin
// 电梯下降
current_floor <= current_floor - 1;
// 到达目标楼层
if (current_floor == next_floor) begin
// 打开电梯门,并清除该楼层的请求
floor_mask <= floor_mask & ~(1 << (current_floor - 1));
// 如果还有请求,继续移动
if (floor_mask != 2'b00) begin
next_floor <= $clog2(floor_mask) - 1;
end else begin
state <= idle;
end
end
end
endcase
end
end
// 按下上行或下行按钮
always @(*) begin
if (up) begin
up_pressed = 1;
end else if (down) begin
down_pressed = 1;
end else begin
up_pressed = 0;
down_pressed = 0;
end
end
// 处理楼层请求
always @(*) begin
if (up_pressed || down_pressed) begin
// 设置请求位
floor_mask <= floor_mask | (1 << (floor_req - 1));
// 如果电梯处于空闲状态,则开始移动
if (state == idle) begin
if (up_pressed) begin
next_floor <= $ffs(floor_mask) - 1;
state <= moving_up;
end else if (down_pressed) begin
next_floor <= $clog2(floor_mask) - 1;
state <= moving_down;
end
end
end
end
endmodule
```
该代码实现了一个简单的四层电梯,包含了上行、下行、楼层请求、电梯状态等功能。
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