用c++写一个解一元二次方程的程序

好的，以下是一个用 C 语言编写的解一元二次方程的程序：

#include <stdio.h>
#include <math.h>

int main() {
    double a, b, c, delta, x1, x2;
    printf("请输入一元二次方程的系数：\n");
    printf("a = ");
    scanf("%lf", &a);
    printf("b = ");
    scanf("%lf", &b);
    printf("c = ");
    scanf("%lf", &c);
    delta = b * b - 4 * a * c;
    if (delta < 0) {
        printf("方程无实数解！\n");
    } else if (delta == 0) {
        x1 = x2 = -b / (2 * a);
        printf("方程有唯一实数解：x1 = x2 = %.2f\n", x1);
    } else {
        x1 = (-b + sqrt(delta)) / (2 * a);
        x2 = (-b - sqrt(delta)) / (2 * a);
        printf("方程有两个实数解：x1 = %.2f，x2 = %.2f\n", x1, x2);
    }
    return 0;
}

希望能够帮到你！

相关问题

用c++写一个解一元二次方程的解，设b²-4ac>0

#include <stdio.h>
#include <math.h>

int main() {
    double a, b, c, delta, x1, x2;
    printf("请输入一元二次方程的系数a, b, c：\n");
    scanf("%lf%lf%lf", &a, &b, &c);

    delta = b * b - 4 * a * c;

    if (delta > 0) {
        x1 = (-b + sqrt(delta)) / (2 * a);
        x2 = (-b - sqrt(delta)) / (2 * a);
        printf("方程的两个实数根为 x1=%.2lf, x2=%.2lf\n", x1, x2);
    } else if (delta == 0) {
        x1 = -b / (2 * a);
        printf("方程有两个相等的实数根 x1=x2=%.2lf\n", x1);
    } else {
        printf("方程没有实数根\n");
    }

    return 0;
}

c++结构体解一元二次方程

以下是一个简单的 C++ 程序，可以用结构体来解一元二次方程：

#include <iostream>
#include <cmath>

using namespace std;

struct QuadraticEquation {
    double a, b, c;
};

int main() {
    QuadraticEquation eq;

    cout << "Enter the coefficients of the quadratic equation (ax^2 + bx + c = 0):" << endl;
    cout << "a = "; cin >> eq.a;
    cout << "b = "; cin >> eq.b;
    cout << "c = "; cin >> eq.c;

    double delta = eq.b * eq.b - 4 * eq.a * eq.c;

    if (delta > 0) {
        double x1 = (-eq.b + sqrt(delta)) / (2 * eq.a);
        double x2 = (-eq.b - sqrt(delta)) / (2 * eq.a);
        cout << "The equation has two real roots: x1 = " << x1 << ", x2 = " << x2 << endl;
    } else if (delta == 0) {
        double x = -eq.b / (2 * eq.a);
        cout << "The equation has one real root: x = " << x << endl;
    } else {
        double realPart = -eq.b / (2 * eq.a);
        double imagPart = sqrt(-delta) / (2 * eq.a);
        cout << "The equation has two complex roots: x1 = " << realPart << " + " << imagPart << "i, x2 = " << realPart << " - " << imagPart << "i" << endl;
    }

    return 0;
}

该程序使用 QuadraticEquation 结构体存储方程的系数，然后计算方程的根（如果有）。如果 delta 大于 0，则方程有两个实数根；如果 delta 等于 0，则方程有一个实数根；否则，方程有两个复数根。