打印出n行杨辉三角python

当然可以，下面是Python代码：

def generate_triangle(n):
    triangle = []
    for i in range(n):
        row = [1] * (i + 1)
        for j in range(1, i):
            row[j] = triangle[i-1][j-1] + triangle[i-1][j]
        triangle.append(row)
    return triangle

def print_triangle(n):
    triangle = generate_triangle(n)
    for row in triangle:
        print(row)

n = 5
print_triangle(n)

输出:

[1]
[1, 1]
[1, 2, 1]
[1, 3, 3, 1]
[1, 4, 6, 4, 1]

相关问题

打印10行杨辉三角python

以下是打印10行杨辉三角的 Python 代码：

n = 10
triangle = []

for i in range(n):
    row = [1] * (i+1)
    for j in range(1, i):
        row[j] = triangle[i-1][j-1] + triangle[i-1][j]
    triangle.append(row)

for row in triangle:
    print(" ".join(str(num) for num in row))

输出结果：

1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
1 5 10 10 5 1
1 6 15 20 15 6 1
1 7 21 35 35 21 7 1
1 8 28 56 70 56 28 8 1
1 9 36 84 126 126 84 36 9 1

写一个打印n行杨辉三角的python代码

以下是打印n行杨辉三角的Python代码：

n = int(input("请输入要打印的行数："))

# 初始化杨辉三角
triangle = [[1]]

# 循环打印每一行
for i in range(1, n):
    row = [1]  # 每一行的第一个数为1
    for j in range(1, i):
        # 当前数等于上一行的两个数之和
        num = triangle[i-1][j-1] + triangle[i-1][j]
        row.append(num)
    row.append(1)  # 每一行的最后一个数为1
    triangle.append(row)

# 打印杨辉三角
for i in range(n):
    print(" "*(n-i), end="")
    for j in range(i+1):
        print(triangle[i][j], end=" ")
    print()

运行结果：

请输入要打印的行数：8
        1 
       1 1 
      1 2 1 
     1 3 3 1 
    1 4 6 4 1 
   1 5 10 10 5 1 
  1 6 15 20 15 6 1 
 1 7 21 35 35 21 7 1