读取文本文件内容 with open("1.txt", "r",encoding='gb18030',errors='ignore') as f: content = f.read();我想把语句中的1.txt更换指定文件夹,应该如何改写
时间: 2024-01-03 14:06:05 浏览: 102
要更换指定文件夹,可以在文件名前加上文件路径。例如,如果要读取名为"1.txt"的文件,它位于路径为"D:\test\"下,则可以按照以下方式改写代码:
```python
with open("D:\\test\\1.txt", "r", encoding='gb18030', errors='ignore') as f:
content = f.read()
```
其中,双反斜杠"\\ "是为了转义反斜杠。如果使用单斜杠"/",需要在文件路径前加上"r"来表示原始字符串,例如:
```python
with open(r"D:/test/1.txt", "r", encoding='gb18030', errors='ignore') as f:
content = f.read()
```
这样就可以读取指定文件夹下的文本文件内容了。
相关问题
with open("1.txt", "r",encoding='gb18030',errors='ignore') as f: content = f.read();我想把1.txt改成变量,因为有时侯不叫这个名字
如果要将文件名改成变量,可以将文件名保存在一个变量中,然后在`open()`函数中使用这个变量。例如:
```python
filename = "my_file.txt" # 将文件名保存在变量中
with open(filename, "r", encoding='gb18030', errors='ignore') as f:
content = f.read()
```
这样,无论文件名是什么,在读取时都可以使用变量`filename`来指定。当然,要保证变量`filename`中保存的是正确的文件名及其路径。
open("508.txt","r",encoding="gb18030",errors=).read()
open("508.txt","r",encoding="gb18030",errors="ignore").read()<span class="em">1</span><span class="em">2</span><span class="em">3</span>
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