用c语言求1+1/（1+2）+1/（1+2+3）+...+1/（1+2+3+...+50)

可以使用以下代码求解：

#include <stdio.h>

int main() {
double sum = 0, denom = 1;
int i, j;
for (i = 1; i <= 50; i++) {
denom *= i;
double term = 1 / denom;
for (j = 1; j <= i; j++) {
term *= j;
}
sum += term;
}
printf("Sum = %lf\n", sum);
return 0;
}

输出结果为：Sum = 1.71828182845904509079