写一份vhdl代码,描述用上位机通过串口控制6个led等的代码
时间: 2024-05-15 08:18:02 浏览: 6
好的,以下是VHDL代码的示例:
```
library ieee;
use ieee.std_logic_1164.all;
use ieee.numeric_std.all;
entity LED_control is
port (
clk : in std_logic;
rst : in std_logic;
data_in : in std_logic_vector(7 downto 0);
enable : in std_logic;
led_out : out std_logic_vector(5 downto 0)
);
end entity;
architecture behavioral of LED_control is
signal buffer : std_logic_vector(47 downto 0);
signal counter : unsigned(5 downto 0) := (others => '0');
signal data_sync : std_logic_vector(7 downto 0);
signal interrupt : std_logic := '0';
begin
process(clk, rst)
begin
if rst = '1' then
buffer <= (others => '0');
counter <= (others => '0');
data_sync <= (others => '0');
interrupt <= '0';
elsif rising_edge(clk) then
if enable = '1' then
if interrupt = '1' then
interrupt <= '0';
if counter = 47 then
counter <= (others => '0');
else
counter <= counter + 1;
end if;
buffer(counter * 8 + 7 downto counter * 8) <= data_sync;
end if;
end if;
end if;
end process;
process(clk, rst)
begin
if rst = '1' then
led_out <= (others => '0');
elsif rising_edge(clk) then
if enable = '1' then
if interrupt = '1' then
led_out <= buffer(5 downto 0);
end if;
end if;
end if;
end process;
process(clk, rst)
begin
if rst = '1' then
data_sync <= (others => '0');
elsif rising_edge(clk) then
if enable = '1' then
if interrupt = '0' then
data_sync <= data_in;
interrupt <= '1';
end if;
end if;
end if;
end process;
end behavioral;
```
这个代码描述了一个能够通过串口控制6个LED灯的电路。具体实现方式是:上位机通过串口将控制数据送入FPGA芯片,在FPGA上触发一个中断,在中断服务程序中将控制数据存入一个缓冲区,并依据计数器将其存入LED灯的对应输出端口。这个代码的基本原理是用VHDL描述出一个状态机,通过状态机控制LED的输出状态,实现LED显示效果的控制。