使用函数实现求下列值++1！+1！+2！+1！+2！+3！+……+1！+2！+3！+……+n！用C语言

以下是使用函数实现求下列值1！+2！+3！+4！+…+10！的C语言代码：

#include <stdio.h>
#include <stdlib.h>

int Factor(int n) //计算n的阶乘
{
    int result = 1;
    for (int i = 1; i <= n; i += 1) {
        result *= i;
    }
    return result;
}

int FactorSum(int n) //计算1！+2！+3！+...+n！
{
    int sum = 0;
    for (int i = 1; i <= n; i += 1) {
        sum += Factor(i);
    }
    return sum;
}

int main()
{
    int n = 10;
    int result = FactorSum(n);
    printf("1!+2!+3!+...+%d! = %d\n", n, result);
    system("pause");
    return 0;
}

相关问题

使用函数实现求下列值++1！+1！+2！+1！+2！+3！+……+1！+2！+3！+……+n！

以下是使用函数实现求下列值的代码：

def Factor(n): #计算n的阶乘
    result = 1
    for i in range(1, n+1):
        result *= i
    return result

def FactorSum(n): #计算1!+2!+3!+...+n!的和
    sum = 0
    for i in range(1, n+1):
        sum += Factor(i)
    return sum

n = 5 #n为5
result = FactorSum(n) #调用函数计算结果
print(result) #输出结果

使用函数实现求下列值 1！+1！+2！+1！+2！+3！+……+1！+2！+3！+……+n！用C语言

以下是使用函数实现求下列值1！+1！+2！+1！+2！+3！+……+1！+2！+3！+……+n！的C语言代码：

#include <stdio.h>
#include <stdlib.h>

int Factor(int n) //计算n的阶乘
{
    int result = 1;
    for (int i = 1; i <= n; i += 1) {
        result *= i;
    }
    return result;
}

int FactorSum(int n) //计算1!+2!+3!+...+n!
{
    int sum = 0;
    for (int i = 1; i <= n; i += 1) {
        for (int j = 1; j <= i; j += 1) {
            sum += Factor(j);
        }
    }
    return sum;
}

int main() {
    int n = 5; //n为5
    int result = FactorSum(n);
    printf("result = %d\n", result); //输出结果
    system("pause");
    return 0;
}