编写C语言1!+2!+……++n!
时间: 2023-11-24 19:51:50 浏览: 39
以下是C语言求1!+2!+……+n!的代码实现:
```c
#include <stdio.h>
int fun(int n) {
int sum = 0, i, j, temp = 1;
for (i = 1; i <= n; i++) {
for (j = 1; j <= i; j++) {
temp *= j;
}
sum += temp; temp = 1;
}
return sum;
}
int main() {
int n;
printf("请输入n的值:");
scanf("%d", &n);
printf("%d的阶乘和为:%d\n", n, fun(n));
return 0;
}
```
相关问题
C语言求1!+2!+……+n!
编写一个函数fun,用于计算1!+2!+3!+ …… +n!的和。在main函数中,从键盘输入n值,并输出运算结果。下面是fun函数的代码实现:
```c
int fun(int n) {
int sum = 0;
int i, j, temp;
for (i = 1; i <= n; i++) {
temp = 1;
for (j = 1; j <= i; j++) {
temp *= j;
}
sum += temp;
}
return sum;
}
```
在main函数中,我们可以这样调用fun函数:
```c
int main() {
int n, result;
printf("请输入n的值:");
scanf("%d", &n);
result = fun(n);
printf("1!+2!+3!+...+n!的和为:%d\n", result);
return 0;
}
```
用C语言递推法编写=1!+2!+3!+……+10!
以下是用C语言递推法编写=1!+2!+3!+……+10!的代码:
```c
#include <stdio.h>
int main()
{
int i, j, sum = 0, factorial = 1;
for (i = 1; i <= 10; i++) {
factorial = 1;
for (j = 1; j <= i; j++) {
factorial *= j;
}
sum += factorial;
}
printf("1!+2!+3!+...+10! = %d\n", sum);
return 0;
}
```