A*算法求解八数码难题(python实现)
时间: 2023-07-10 20:31:10 浏览: 129
八数码问题(8皇后问题)的A*算法求解(Python实现)
好的,以下是Python实现A*算法求解八数码难题的代码:
```python
import heapq
# 定义状态类
class PuzzleState:
def __init__(self, board, goal, moves=0):
self.board = board
self.goal = goal
self.moves = moves
# 计算当前状态的哈曼顿距离
def manhattan_distance(self):
distance = 0
for i in range(3):
for j in range(3):
if self.board[i][j] == 0:
continue
distance += abs(i - (self.board[i][j] - 1) // 3) + abs(j - (self.board[i][j] - 1) % 3)
return distance
# 定义状态比较函数,用于堆排序
def __lt__(self, other):
return self.moves + self.manhattan_distance() < other.moves + other.manhattan_distance()
# 判断当前状态是否为目标状态
def is_goal(self):
return self.board == self.goal
# 生成当前状态的所有合法后继状态
def generate_successors(self):
successors = []
i, j = next((i, j) for i in range(3) for j in range(3) if self.board[i][j] == 0)
for x, y in ((i - 1, j), (i + 1, j), (i, j - 1), (i, j + 1)):
if 0 <= x < 3 and 0 <= y < 3:
successor = [row[:] for row in self.board]
successor[i][j], successor[x][y] = successor[x][y], successor[i][j]
successors.append(PuzzleState(successor, self.goal, self.moves + 1))
return successors
# 定义A*搜索函数
def solve_puzzle(start, goal):
frontier = [start]
heapq.heapify(frontier)
explored = set()
while frontier:
state = heapq.heappop(frontier)
if state.is_goal():
return state.moves, explored
explored.add(str(state.board))
for successor in state.generate_successors():
if str(successor.board) not in explored:
heapq.heappush(frontier, successor)
return None
# 测试代码
start = [[2, 8, 3], [1, 6, 4], [7, 0, 5]]
goal = [[1, 2, 3], [8, 0, 4], [7, 6, 5]]
start_state = PuzzleState(start, goal)
moves, explored = solve_puzzle(start_state, goal)
print("Minimum number of moves:", moves)
print("Number of explored states:", len(explored))
```
其中,`PuzzleState`类表示八数码难题的一个状态,包含当前棋盘状态`board`、目标状态`goal`和已经移动的步数`moves`。`manhattan_distance`方法计算当前状态和目标状态之间的哈曼顿距离,用于A*算法的估价函数。`__lt__`方法定义状态比较函数,用于堆排序。`is_goal`方法判断当前状态是否为目标状态。`generate_successors`方法生成当前状态的所有合法后继状态。`solve_puzzle`函数实现A*算法的搜索过程,返回最少移动步数和搜索过的状态数量。测试代码给出了一个初始状态和目标状态,可以根据需要修改。
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