double PurePursuitController::judge_lr(const TrajectoryPoint& start_point, const TrajectoryPoint& end_point, const TrajectoryPoint& j_point) { double is_prec = (start_point.path_point.y - end_point.path_point.y) * j_point.path_point.x + (end_point.path_point.x - start_point.path_point.x) * j_point.path_point.y + start_point.path_point.x * end_point.path_point.y - end_point.path_point.x * start_point.path_point.y; if (is_reverse) { is_prec = (end_point.path_point.y - start_point.path_point.y) * j_point.path_point.x + (start_point.path_point.x - end_point.path_point.x) * j_point.path_point.y + start_point.path_point.y * end_point.path_point.x - end_point.path_point.y * start_point.path_point.x; } double np = is_prec > 0.0 ? 1.0 : (-1.0); return np; }

LeetCode与在线评测系统：探索hello_world_ints项目

资源摘要信息: "LeetCode和在线判题系统(Online Judge, OJ)的相关知识点介绍" LeetCode和在线判题系统(OJ)是程序员和算法爱好者常用的编程练习和算法竞赛平台。LeetCode提供了丰富的编程题目，涵盖了从基础数据结构...

栈操作挑战：3012 Lines Judge的逻辑解析

资源摘要信息:"3012_lines_judge_" ### 标题解析标题 "3012_lines_judge_" 指的可能是某个具体的编程问题或者算法测试题目。通常这类标题表示了一个在线评测系统中的一个测试案例编号，该编号可能关联到具体的...

def judge_color(self,row, col, color, direct): if self.judge_owner(row, col, color, direct): self.judge_colory = False else: self.judge_colory = True def judge_next(self, color): if color == 1: return 2 else: return 1

judge_color 方法用于判断是否存在获胜方。根据给定的行、列、颜色和方向，调用 judge_owner 方法来判断是否存在获胜方。如果存在获胜方，将 self.judge_colory 设置为 False；否则将其设置为 True。 judge_...

error C2664: 'int JUDGE_VARIABLE(char ,int,LUINT,double,double,double,char )' : cannot convert argument 6 from 'const char [17]' to 'double'

这个错误的意思是你正在尝试将一个字符串类型的值传递给一个需要 double 类型的参数的函数。请检查你的代码，确定参数列表中第六个参数应该是一个 double 类型的值。如果你确定要传递一个字符串类型的值，需要先将其...

帮我优化一下这段python代码 import datetime class error: def init(self, log_path): pass self.log_path = log_path self.port = port self.end_time = end_time self.start_time = start_time def network_error(self, log_path: str, port: str, end_time: float, start_time: float = 0): with open(log_path, 'r') as f: for line in f.readlines(): log_time_str = line.split()[0] # 就看第一个是不是时间，如何是是时间戳的话看下要不要转 datetime_object = datetime.datetime.strptime( log_time_str, '%Y-%m-%d %H:%M:%S') log_time = datetime_object.timestamp() if start_time <= log_time <= end_time: if port in line: return True def no_finf_element(self, log_path: str, end_time: float, start_time: float = 0): with open(log_path, 'r') as f: for line in f.readlines(): log_time_str = line.split()[0] # 就看第一个是不是时间，如何是是时间戳的话看下要不要转 datetime_object = datetime.datetime.strptime( log_time_str, '%Y-%m-%d %H:%M:%S') log_time = datetime_object.timestamp() if start_time <= log_time <= end_time: if 'no such element' in line: return True def error_judge(self): if network_error(self.log_path, self.port, self.end_time, self.start_time) == True and no_finf_elemen(self.log_path, self.end_time, self.start_time) == True: pass # 不执行重跑 else: pass # 执行重跑

return self._check_error(self.log_path, self.end_time, self.start_time, 'no such element') def error_judge(self): if self.network_error() and self.no_finf_element(): pass # 不执行重跑 else: ...

def __next_step(self, x, y): if not self.judge_colory: self.history += 0 else: self.history += 1 self.color = 1 if self.__history % 2 == 0 else 2 if self.start_ai_game: if self.ai_color == self.color: row,col = self.ai_stage(self.ai_game()[0],self.ai_game()[1]) else: col = round((x-self.margin2)/self.cell_width) row = round((y-self.margin2)/self.cell_width) stage_row = (y-self.margin)-(self.cell_widthrow+self.__margin) stage_col = (x-self.margin)-(self.cell_widthcol+self.__margin) if stage_col < stage_row: self.direct= 1 else: self.direct= 0 else: col = round((x - self.margin * 2) / self.cell_width) row = round((y - self.margin * 2) / self.cell_width) stage_row = (y - self.margin) - (self.cell_width * row + self.__margin) stage_col = (x - self.margin) - (self.cell_width * col + self.__margin) if stage_col < stage_row: self.direct = 1 else: self.direct= 0 if self.valide(row, col, self.direct): if self.history % 4 == 0 or (self.history + 2) % 4 == 0: self.__game_board.drew_turn(2) else: self.__game_board.drew_turn(1) self.add_logic(row, col, self.color) self.__game_board.draw_chess(row, col, self.color, self.direct) if self.judge_owner(row, col, self.color, self.direct): self.__game_board.drew_turn(self.judge_next(self.color)) for i in self.judge_owner(row, col, self.color, self.direct): x,y=self.draw_owner(i) self.__game_board.drew_owner(self.color, y, x) else: self.__game_board.drew_turn(self.color) self.judge_color(row, col, self.color, self.direct) print(self.logic_board_state) if 0 not in self.logic_board_owner: self.__game_board.pop_win(self.judge_winner())

如果 self.start_ai_game 为真，则进入 AI 对战模式。根据当前的颜色和 AI 的颜色判断是否轮到 AI 下棋。如果是，则调用 self.ai_stage 方法，传入当前棋盘状态和当前颜色，获取 AI 下棋的结果，并将结果赋值给 ...

codeforcesleetcode-Competitive-Programming::face_blowing_a_kiss:竞技编程源代码（OnlineJudge,ICPC,CC

代码力量 leetcode 竞争性编程竞技编程的源代码代码力量编码器顶级编码器海多杰 POJ BZOJ 梦想中杰 51点头 LibreOJ 福州大学 GCJ hihocoder 力码编码面试等等去做

Polygon_Intersection_Solver：KTU编程语言讲座的Python OOP分配（https：onlinejudge.orgindex.php？option = com_onlinejudge＆Itemid = 8＆category = 530＆page = show_problem＆problem = 1262）

《Polygon_Intersection_Solver：KTU编程语言讲座的Python OOP实战解析》在计算机科学领域，几何算法是处理图形和空间数据的关键部分。Polygon_Intersection_Solver项目，源自KTU（Kazakh-Turkish University）...

Java版水果管理系统源码-InterView-Q-A::man_judge:面试问答

Java版水果管理系统源码前端面试Q&A TypeScript和ES6的区别 TypeScript是一种由微软开发的自由和开源的编程语言。而且本质上向这个语言添加了可选的静态类型和基于类的面向对象编程。安德斯·海尔斯伯格，C#的首席...

baekjoon:yarncha的Baekjoon算法问题解决:smiling_face_with_smiling_eyes:

qwreq"，这些似乎是编码题目编号或描述，但它们在常规的Baekjoon Online Judge（BOJ）平台上没有对应的格式。由于这些信息并不清晰，我们将主要关注"Baekjoon算法问题解决"这个主题，并结合"C++"这一标签来探讨在...

myAlgorithms:나의PS알고리즘스소‍:man_light_skin_tone:

在百柱（也称为Baekjoon Online Judge）这个在线编程挑战平台上，用户可以找到各种难度级别的算法题目，涵盖了从基础的数据结构和算法到高级的复杂问题。通过解决这些题目，开发者可以提升自己的编程技巧，深入理解...

leetcode和oj-Search_Prefix_Suffix:搜索_前缀_后缀

在编程领域，LeetCode 和 Online Judge (OJ) 是两个非常重要的资源，它们为程序员提供了大量的编程题目，帮助他们提升算法技巧和问题解决能力。"Search_Prefix_Suffix" 这个主题涉及到的是字符串处理中的一种常见...

#include "myapp.h" myapp::myapp(QObject *parent) : QObject(parent) { //创建并打开SQLite数据库 this->mydb = new SqOperator; mydb->openDb(); //创建数据表 mydb->createTable(); //这里分别新建的是登录和注册两个对象 this->login = new mylogin; this->login->show(); this->enroll = new myenroll; this->face = new chatInterface; this->tip = new tips; connect(login,&mylogin::sig_login,this,&myapp::judge); connect(login,&mylogin::sig_enroll,this,&myapp::show_enroll_face); connect(enroll,&myenroll::sig_enroll_info,this,&myapp::insertdb); } bool myapp::judge(QString usrname, QString usrpass) { qDebug()<<usrname<<usrpass; //查询全部数据,并且放入list中 QList<QString> list; mydb->queryTable(list); int i = 0; //当存在两个账号的时候，这里循环里面的if必定会进去，错误和正确都会提示，应该在正确之后直接结束判断，而错误提示则应该放在循环结束 for(i = 0 ; i < list.size() ; i=i+2) { if(usrname == list[i] || usrpass == list[i+1]) { this->face->show(); return true; } } this->tip->loginfail(); return false; } void myapp::show_enroll_face() { this->enroll->show(); } void myapp::insertdb(QString usrname,QString usrpass) { qDebug()<<usrname<<usrpass; info info1; info1.usrname = usrname; info1.usrpass = usrpass; if(mydb->singleInsertData(info1)) { this->tip->insertok(); } }用C++解释每一行代码的语法和作用

bool myapp::judge(QString usrname, QString usrpass) { //myapp类的judge函数，返回值为bool类型，传入两个QString类型的参数usrname和usrpass qDebug(); //输出usrname和usrpass参数的值 //查询全部数据,并且...

list_num = [] * 100 sum = 0 n,a,b = map(int, input().split()) for i in range(n): list_num.append(input().split(' ')) list_num[i] = list(map(int, list_num[i])) def calculate_sum(n, a, b, sum, list_num): for i in range(n): sum = sum + judge(a, b, list_num[i]) return sum def calculate_w(a, b, list_): if (list_[0] <= 0): if (list_[2] < a): return list_[2] else: return a else: if (list_[2] < a): return list_[2] - list_[0] else: return a - list_[0] def calculate_l(a, b, list_): if (list_[1] <= 0): if (list_[3] < b): return list_[3] else: return b else: if (list_[3] < b): return list_[3] - list_[0] else: return b - list_[0] def calculate(a, b, list_): return calculate_w(a, b, list_) * calculate_l(a, b, list_) def judge(a, b, list_): if (list_[0] > 0 and list_[1] > 0 and list_[2] < a and list_[3] < b): return ((list_[2] - list_[0]) * (list_[3] - list_[1])) elif (list_[0] >= a or list_[1] >= b or list_[2] <= 0 or list_[3] <= 0): return 0 else: return calculate(a, b, list_) if name == 'main': print(calculate_sum(n, a, b, sum, list_num))转c++

int judge(int a, int b, vector<int>& list_) { if (list_[0] > 0 && list_[1] > 0 && list_[2] < a && list_[3] ) { return ((list_[2] - list_[0]) * (list_[3] - list_[1])); } else if (list_[0] >= a || ...

AttributeError: 'GUI_judge_databasequery' object has no attribute 'initface'

这错误通常意味着在GUI_judge_databasequery类中没有定义名为initface的方法。请检查你的代码并确保在类中定义了此方法。还要检查是否有任何拼写错误或其他语法错误。你可以在类中添加以下代码来定义initface方法： ...

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