java石头剪刀布while实现

在Java中实现"石头、剪刀、布"游戏的While循环版本，通常会涉及到用户输入判断以及随机电脑选择。下面是一个简单的示例：

import java.util.Random;
import java.util.Scanner;

public class RockPaperScissors {
    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);
        Random random = new Random();

        System.out.println("Let's play Rock-Paper-Scissors!");
        while (true) {
            System.out.print("Enter your choice (rock, paper, scissors): ");
            String userChoice = input.nextLine().toLowerCase();

            if (!("rock".equals(userChoice) || "paper".equals(userChoice) || "scissors".equals(userChoice))) {
                System.out.println("Invalid choice! Please try again.");
                continue;
            }

            // Generate a random computer choice
            int computerChoice = random.nextInt(3);
            String[] choices = {"rock", "paper", "scissors"};
            String computerChoiceStr = choices[computerChoice];

            System.out.println("Computer chose: " + computerChoiceStr);

            // Determine the winner based on the rules
            if ((userChoice.equals("rock") && computerChoiceStr.equals("scissors")) ||
                    (userChoice.equals("paper") && computerChoiceStr.equals("rock")) ||
                    (userChoice.equals("scissors") && computerChoiceStr.equals("paper"))) {
                System.out.println("You win!");
            } else if (userChoice.equals(computerChoiceStr)) {
                System.out.println("It's a tie!");
            } else {
                System.out.println("You lose!");
            }

            // Ask for another round or quit
            System.out.print("Do you want to play again? Type 'yes' or 'no': ");
            String playAgain = input.nextLine();
            if (!"yes".equalsIgnoreCase(playAgain)) {
                break;
            }
        }
        input.close();
    }
}

在这个游戏中，玩家通过键盘输入选择，然后计算机随机出拳。程序会根据规则判断胜负，并询问是否再玩一轮。如果用户输入不是"yes"，则退出游戏。