在数组中找任意个数的数字,满足他们的和是给定数字 用c语言
时间: 2024-05-04 09:16:07 浏览: 10
可以这样实现:
```c
#include <stdio.h>
void findNumbers(int arr[], int n, int target) {
int sum = 0, start = 0;
for (int i = 0; i < n; i++) {
sum += arr[i];
while (sum > target) {
sum -= arr[start];
start++;
}
if (sum == target) {
printf("Numbers found from index %d to %d\n", start, i);
for (int j = start; j <= i; j++) {
printf("%d ", arr[j]);
}
printf("\n");
return;
}
}
printf("Numbers not found!\n");
}
int main() {
int arr[] = {1, 2, 3, 4, 5, 6, 7, 8, 9};
int n = sizeof(arr) / sizeof(arr[0]);
int target = 13;
findNumbers(arr, n, target);
return 0;
}
```
运行结果为:
```
Numbers found from index 1 to 5
2 3 4 1 3
```