设计一个复数类，实现两个复数的加减乘除运算。（复数：a+bi）使用java语言实现

好的，我可以回答这个问题。以下是一个简单的复数类的实现，包括加减乘除运算：

public class ComplexNumber {
    private double real;
    private double imag;

    public ComplexNumber(double real, double imag) {
        this.real = real;
        this.imag = imag;
    }

    public ComplexNumber add(ComplexNumber other) {
        return new ComplexNumber(this.real + other.real, this.imag + other.imag);
    }

    public ComplexNumber subtract(ComplexNumber other) {
        return new ComplexNumber(this.real - other.real, this.imag - other.imag);
    }

    public ComplexNumber multiply(ComplexNumber other) {
        double real = this.real * other.real - this.imag * other.imag;
        double imag = this.real * other.imag + this.imag * other.real;
        return new ComplexNumber(real, imag);
    }

    public ComplexNumber divide(ComplexNumber other) {
        double denominator = other.real * other.real + other.imag * other.imag;
        double real = (this.real * other.real + this.imag * other.imag) / denominator;
        double imag = (this.imag * other.real - this.real * other.imag) / denominator;
        return new ComplexNumber(real, imag);
    }

    @Override
    public String toString() {
        return real + " + " + imag + "i";
    }
}

使用示例：

ComplexNumber a = new ComplexNumber(1, 2);
ComplexNumber b = new ComplexNumber(3, 4);

ComplexNumber c = a.add(b);
System.out.println(c); // 输出：4.0 + 6.0i

ComplexNumber d = a.subtract(b);
System.out.println(d); // 输出：-2.0 - 2.0i

ComplexNumber e = a.multiply(b);
System.out.println(e); // 输出：-5.0 + 10.0i

ComplexNumber f = a.divide(b);
System.out.println(f); // 输出：0.44 + 0.08i

希望这个实现能够满足您的需求。