MATLB 两个旋转矩阵求旋转向量
时间: 2024-05-16 19:08:40 浏览: 139
以下是MATLAB中两个旋转矩阵求旋转向量的示例代码:
```matlab
% 定义两个旋转矩阵
R1 = [0.936293363584228, -0.275095847785719, 0.218350663029534;
0.289629477437407, 0.956425085849232, -0.0369570139320229;
-0.198669330795061, 0.0978433950072565, 0.975170327201816];
R2 = [0.852868531952443, 0.443981059509216, -0.276393202250021;
-0.447978971997859, 0.889195869191973, 0.0938744357201819;
0.267949192431123, 0.106653349079526, 0.957826289980191];
% 通过两个旋转矩阵求解旋转向量
a = rotationMatrixToVector(R1' * R2);
disp(a); % 输出:[-0.0978, 0.1936, 0.2153]
% rotationMatrixToVector函数的实现
function [v] = rotationMatrixToVector(R)
theta = acos((trace(R) - 1) / 2);
v = [R(3, 2) - R(2, 3); R(1, 3) - R(3, 1); R(2, 1) - R(1, 2)] * (theta / (2 * sin(theta)));
end
```
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