设计一个任意整数数控分频器,其分频系数(1-255)由外部的8位数控制。要求使用VHDL语言实现,并仿真,以及仿真步骤
时间: 2024-03-20 12:40:22 浏览: 75
好的,我可以为你设计一个任意整数数控分频器,以下是VHDL语言实现的代码:
```vhdl
entity div is
port (
clk_in : in std_logic;
rst : in std_logic;
div_in : in std_logic_vector(7 downto 0);
clk_out : out std_logic
);
end div;
architecture Behavioral of div is
signal cnt : integer range 0 to 255;
signal div_cnt : integer range 0 to 255;
begin
process(clk_in, rst)
begin
if rst = '1' then
cnt <= 0;
div_cnt <= 0;
clk_out <= '0';
elsif rising_edge(clk_in) then
if cnt = div_in then
clk_out <= not clk_out;
cnt <= 0;
else
cnt <= cnt + 1;
end if;
end if;
end process;
end Behavioral;
```
其中,div_in是8位数控信号,控制分频系数,clk_in是输入时钟信号,clk_out是输出时钟信号,rst是复位信号。
仿真步骤如下:
1. 编写测试文件,设置时钟信号和复位信号
2. 实例化div模块,并连接时钟、复位和数控信号
3. 运行仿真
以下是测试文件的代码示例:
```vhdl
library ieee;
use ieee.std_logic_1164.all;
use ieee.numeric_std.all;
entity div_tb is
end div_tb;
architecture Behavioral of div_tb is
component div is
port (
clk_in : in std_logic;
rst : in std_logic;
div_in : in std_logic_vector(7 downto 0);
clk_out : out std_logic
);
end component;
signal clk_in : std_logic := '0';
signal rst : std_logic := '1';
signal div_in : std_logic_vector(7 downto 0) := x"10";
signal clk_out : std_logic;
begin
DUT : div
port map (
clk_in => clk_in,
rst => rst,
div_in => div_in,
clk_out => clk_out
);
stim_proc : process
begin
rst <= '1';
clk_in <= '0';
div_in <= x"10";
wait for 10 ns;
rst <= '0';
for i in 0 to 255 loop
div_in <= std_logic_vector(to_unsigned(i, 8));
wait for 100 ns;
end loop;
wait;
end process;
end Behavioral;
```
以上代码中,时钟信号clk_in的频率为10ns,数控信号div_in在0~255之间循环,并每隔100ns进行一次变化。
最后,运行仿真,查看输出时钟信号是否符合分频系数的要求。
阅读全文