遍历csv文件中第七列的值，判断其是否与前后相邻行的值不一样，如果不一样则判断其对应的相邻时间差，若时间小于2分钟则删除这一行

以下是Python代码实现：

import csv
import datetime

filename = 'data.csv'

# 读取csv文件
with open(filename, 'r', newline='') as csvfile:
    reader = csv.reader(csvfile)
    rows = [row for row in reader]

# 遍历第七列的值
for i in range(1, len(rows)-1):
    current_val = rows[i][6]
    prev_val = rows[i-1][6]
    next_val = rows[i+1][6]
    
    if current_val != prev_val and current_val != next_val:
        current_time = datetime.datetime.strptime(rows[i][0], '%Y-%m-%d %H:%M:%S')
        prev_time = datetime.datetime.strptime(rows[i-1][0], '%Y-%m-%d %H:%M:%S')
        next_time = datetime.datetime.strptime(rows[i+1][0], '%Y-%m-%d %H:%M:%S')
        
        if (current_time - prev_time).total_seconds() < 120 or (next_time - current_time).total_seconds() < 120:
            del rows[i]

# 将处理后的数据写入新的csv文件
with open('new_data.csv', 'w', newline='') as csvfile:
    writer = csv.writer(csvfile)
    writer.writerows(rows)

其中，`datetime.datetime.strptime()`函数用于将字符串转换为datetime对象，`total_seconds()`函数用于计算两个datetime对象之间的时间差（以秒为单位）。