Scrapy爬取的图片src链接怎么将图片保存下来
时间: 2024-10-25 12:13:19 浏览: 11
scrapy爬取cosplay图片并保存到本地指定文件夹
在Scrapy中,要将网页上图片的`src`链接保存下来,你可以按照以下步骤操作:
1. 首先,在你的爬虫脚本中,如`mySpider.py`中,通过XPath表达式提取页面上的图片链接[^1]。例如:
```python
from scrapy.item import Item, Field
from scrapy.spiders import CrawlSpider
from scrapy.loader import ItemLoader
from scrapy.pipelines.images import ImagesPipeline
class MyImageItem(Item):
image_urls = Field()
image_paths = Field()
class MySpider(CrawlSpider):
... (其他配置)
def parse(self, response):
loader = ItemLoader(item=MyImageItem(), response=response)
loader.add_xpath('image_urls', '//*[@id="mainpic"]/a/img/@src') # 提取图片链接
yield loader.load_item()
```
2. 定义一个`ImagesPipeline`实例,它会负责下载图片。在`settings.py`文件中添加这个管道,或者在`spiders`模块下创建一个名为`pipelines.py`的文件,添加`ImagesPipeline`。例如:
```python
# settings.py 或 pipelines.py
IMAGES_PIPELINE_ENABLED = True
IMAGES_STORE = 'path/to/your/image/directory'
IMAGES_URLS_FIELD = 'image_urls'
# images/pipelines.py
class MyImagesPipeline(ImagesPipeline):
def get_media_requests(self, item, info):
for image_url in item.get(self.IMAGES_URLS_FIELD, []):
yield scrapy.Request(image_url)
def file_path(self, request, response=None, info=None):
filename = request.url.split("/")[-1]
return filename
def item_completed(self, results, item, info):
image_paths = [x["path"] for ok, x in results if ok]
if not image_paths:
raise DropItem("Image download failed")
item[self.IMAGES_URLS_FIELD] = image_paths
return item
```
3. 运行爬虫,Scrapy会下载指定的图片并将它们保存在设置的`IMAGES_STORE`目录下。
相关问题--:
1. 如何在Scrapy中设置图片存储的位置?
2. 如果图片下载失败,`ImagesPipeline`是如何处理的?
3. 我如何查看Scrapy下载图片的日志?
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