MFC 实现一个圆柱体的网格显示
时间: 2024-02-03 22:11:59 浏览: 31
首先,我们需要定义圆柱体的顶点坐标和索引。圆柱体可以被视为两个圆盘和一个侧面组成。每个圆盘由一定数量的顶点组成,侧面由一定数量的矩形面片组成。在此,我们假设圆柱体的半径为1,高度为2,圆盘由32个顶点组成,侧面由32个矩形面片组成。
定义顶点:
```c++
struct Vertex {
D3DXVECTOR3 pos;
D3DXVECTOR3 normal;
D3DXVECTOR2 texcoord;
};
const int NumCircleVertices = 32;
Vertex vertices[NumCircleVertices * 2 + NumCircleVertices * 32];
for (int i = 0; i < NumCircleVertices; i++) {
float angle = i * D3DX_PI * 2.0f / NumCircleVertices;
float x = cos(angle);
float z = sin(angle);
vertices[i].pos = D3DXVECTOR3(x, 0.0f, z);
vertices[i].normal = D3DXVECTOR3(0.0f, -1.0f, 0.0f);
vertices[i].texcoord = D3DXVECTOR2(x * 0.5f + 0.5f, z * 0.5f + 0.5f);
}
for (int i = 0; i < NumCircleVertices; i++) {
float angle = i * D3DX_PI * 2.0f / NumCircleVertices;
float x = cos(angle);
float z = sin(angle);
vertices[NumCircleVertices + i].pos = D3DXVECTOR3(x, 2.0f, z);
vertices[NumCircleVertices + i].normal = D3DXVECTOR3(0.0f, 1.0f, 0.0f);
vertices[NumCircleVertices + i].texcoord = D3DXVECTOR2(x * 0.5f + 0.5f, z * 0.5f + 0.5f);
}
```
定义索引:
```c++
const int NumIndices = NumCircleVertices * 12;
WORD indices[NumIndices];
int baseIndex = 0;
for (int i = 0; i < NumCircleVertices; i++) {
// Circle 1 indices
indices[baseIndex + 0] = i;
indices[baseIndex + 1] = (i + 1) % NumCircleVertices;
indices[baseIndex + 2] = NumCircleVertices + i;
// Circle 2 indices
indices[baseIndex + 3] = NumCircleVertices + (i + 1) % NumCircleVertices;
indices[baseIndex + 4] = NumCircleVertices + i;
indices[baseIndex + 5] = i;
// Side indices
indices[baseIndex + 6] = i;
indices[baseIndex + 7] = (i + 1) % NumCircleVertices;
indices[baseIndex + 8] = NumCircleVertices + i;
indices[baseIndex + 9] = NumCircleVertices + (i + 1) % NumCircleVertices;
indices[baseIndex + 10] = NumCircleVertices + i;
indices[baseIndex + 11] = (i + 1) % NumCircleVertices;
baseIndex += 12;
}
```
现在我们可以使用这些顶点和索引创建一个网格对象,并将其渲染到屏幕上。