你能用python写一个扫雷游戏的代码吗

当然可以！以下是一个简单的扫雷游戏实现：

import random

# 雷区大小
ROWS = 10
COLS = 10
MINES = 10

# 定义格子状态
HIDDEN = 0
VISIBLE = 1
MARKED = 2

# 定义雷区
minefield = [[0 for j in range(COLS)] for i in range(ROWS)]

# 安放地雷
count = 0
while count < MINES:
    row = random.randint(0, ROWS - 1)
    col = random.randint(0, COLS - 1)
    if minefield[row][col] == 0:
        minefield[row][col] = -1
        count += 1

# 计算周围雷的数量
for i in range(ROWS):
    for j in range(COLS):
        if minefield[i][j] == -1:
            continue
        for x in range(max(0, i - 1), min(ROWS, i + 2)):
            for y in range(max(0, j - 1), min(COLS, j + 2)):
                if minefield[x][y] == -1:
                    minefield[i][j] += 1

# 定义游戏状态
game_over = False
game_win = False

# 显示雷区
def show_minefield():
    for i in range(ROWS):
        for j in range(COLS):
            if minefield[i][j] == -1:
                print("*", end=" ")
            elif minefield[i][j] == HIDDEN:
                print(".", end=" ")
            elif minefield[i][j] == VISIBLE:
                print(minefield[i][j], end=" ")
            elif minefield[i][j] == MARKED:
                print("P", end=" ")
        print()

# 点击格子
def click(row, col):
    global game_over, game_win
    if minefield[row][col] == -1:
        game_over = True
    else:
        minefield[row][col] = VISIBLE
        if minefield[row][col] == 0:
            for x in range(max(0, row - 1), min(ROWS, row + 2)):
                for y in range(max(0, col - 1), min(COLS, col + 2)):
                    if minefield[x][y] == HIDDEN:
                        click(x, y)
        if all(minefield[i][j] != HIDDEN for i in range(ROWS) for j in range(COLS) if minefield[i][j] != -1):
            game_win = True

# 标记格子
def mark(row, col):
    if minefield[row][col] == HIDDEN:
        minefield[row][col] = MARKED
    elif minefield[row][col] == MARKED:
        minefield[row][col] = HIDDEN

# 游戏循环
while not game_over and not game_win:
    show_minefield()
    row = int(input("请输入行号(0~{}): ".format(ROWS - 1)))
    col = int(input("请输入列号(0~{}): ".format(COLS - 1)))
    action = input("请输入操作(C表示标记，其他表示点击): ")
    if action == "C":
        mark(row, col)
    else:
        click(row, col)

# 游戏结束
show_minefield()
if game_win:
    print("恭喜你，你赢了！")
else:
    print("很遗憾，你输了！")

此程序包含了一个简单的命令行界面，可以让玩家点击格子来揭开地图或标记可能的地雷位置。游戏结束后会显示整个雷区，告诉玩家是否胜利。