在R中,运行以下代码时:# 生成随机数据集 set.seed(1) data <- matrix(rnorm(50*30), nrow = 50) colnames(data) <- paste0("V", 1:30) y1 <- data %*% rnorm(30, mean = 2, sd = 0.5) y2 <- data %*% rnorm(30, mean = 1, sd = 0.3) y3 <- data %*% rnorm(30, mean = 3, sd = 0.7) # 线性回归模型 data <- as.data.frame(data) lm.fit1 <- lm(y1 ~ ., data = data) lm.fit2 <- lm(y2 ~ ., data = data) lm.fit3 <- lm(y3 ~ ., data = data) data <- as.data.frame(lapply(data, as.numeric)) # 计算 CV 值 library(boot) cv.error1 <- cv.glm(data, lm.fit1)$delta[1]。出现了以下问题:Error in model.frame.default(formula = y1 ~ ., data = list(V1 = c(-0.626453810742332, : 变数的长度不一样('V1')。。请从头至尾对代码的表达逻辑进行更改,并解决该问题
时间: 2024-02-22 07:54:53 浏览: 165
根据错误提示,出现问题的是变量的长度不一致。错误发生在最后一行代码,因为在前面的代码中,data已经被转换为data.frame类型,并且其中所有变量的长度应该是一致的。因此,问题可能出现在数据生成的过程中。
可以尝试以下修改,将数据生成的过程和变量命名的过程分开:
```R
# 生成随机数据集
set.seed(1)
data <- matrix(rnorm(50*30), nrow = 50)
y1 <- data %*% rnorm(30, mean = 2, sd = 0.5)
y2 <- data %*% rnorm(30, mean = 1, sd = 0.3)
y3 <- data %*% rnorm(30, mean = 3, sd = 0.7)
# 将数据转换为data.frame类型,并且为变量命名
data <- as.data.frame(data)
colnames(data) <- paste0("V", 1:30)
# 线性回归模型
lm.fit1 <- lm(y1 ~ ., data = data)
lm.fit2 <- lm(y2 ~ ., data = data)
lm.fit3 <- lm(y3 ~ ., data = data)
# 将数据转换为numeric类型
data <- as.data.frame(lapply(data, as.numeric))
# 计算 CV 值
library(boot)
cv.error1 <- cv.glm(data, lm.fit1)$delta[1]
```
这样可以确保数据的每一列都被正确地命名,并且在生成数据时也不会出现问题。如果还有其他问题,可以再进一步检查。
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