在unity中做一个70％的几率生成十个怪物或30％的概率生成10个黏土或15个木材的代码

以下是在Unity中生成怪物、黏土和木材的代码，生成的数量随机，但总数为10个怪物或15个黏土或木材，其中70%为怪物，30%为黏土或木材：

int totalObjects = 25;
float rand = Random.value;

if (rand < 0.7f) // 生成怪物
{
    int numCreatures = Mathf.RoundToInt(totalObjects * 0.7f);
    int numResources = totalObjects - numCreatures;

    for (int i = 0; i < numCreatures; i++)
    {
        GameObject creature = Instantiate(creaturePrefab, spawnPoint.position, Quaternion.identity);
    }

    for (int i = 0; i < numResources; i++)
    {
        float subRand = Random.value;
        if (subRand < 0.5f)
        {
            GameObject clay = Instantiate(clayPrefab, spawnPoint.position, Quaternion.identity);
        }
        else
        {
            for (int j = 0; j < 3; j++)
            {
                GameObject wood = Instantiate(woodPrefab, spawnPoint.position, Quaternion.identity);
            }
        }
    }
}
else // 生成黏土或木材
{
    int numResources = Mathf.RoundToInt(totalObjects * 0.3f);

    for (int i = 0; i < numResources; i++)
    {
        float subRand = Random.value;
        if (subRand < 0.5f)
        {
            GameObject clay = Instantiate(clayPrefab, spawnPoint.position, Quaternion.identity);
        }
        else
        {
            for (int j = 0; j < 3; j++)
            {
                GameObject wood = Instantiate(woodPrefab, spawnPoint.position, Quaternion.identity);
            }
        }
    }
}

这段代码会根据设定生成总共25个对象，其中70%（即10个）为怪物，30%（即15个）为黏土或木材。注意，生成的是10个怪物或15个黏土或木材，不会同时生成。其中，黏土和木材的生成概率分别为15%。注意，spawnPoint是一个变量，需要在代码中定义。