跳棋小游戏python代码人机对战

编写一个简单的Python跳棋小游戏的人机对战，我们可以使用基本的控制台界面和简单的游戏逻辑。这里是一个基本框架的概述：

# 导入必要的模块
import random

# 定义棋盘大小和初始棋子位置
BOARD_SIZE = 8
CHessPiece = ['X', 'O']  # X代表玩家，O代表电脑

def create_board():
    board = [[' ' for _ in range(BOARD_SIZE)] for _ in range(BOARD_SIZE)]
    return board

def place_piece(board, piece, position):
    board[position][position] = piece

def check_win(board, piece):
    # 检查四方向是否有连续的棋子
    for dx, dy in [(0, 1), (1, 0), (0, -1), (-1, 0)]:
        for i in range(len(board) - 2):
            if board[i][i + dx] == piece and board[i + 1][i + dx + dy] == piece and \
                    board[i + 2][i + dx + 2 * dy] == piece:
                return True
    return False

def make_move(board, player, AI_turn):
    if AI_turn:
        available_moves = find_available_moves(board, CHessPiece[1-player])
        if available_moves:
            return random.choice(available_moves)
        else:
            print("电脑无法移动，平局或你赢了！")
            return None
    else:
        position = input(f"{player} 的回合，请输入你要落子的位置 (行, 列): ")
        position = map(int, position.split(','))
        return position

def main():
    board = create_board()
    player = 'X'
    AI_turn = True
    while True:
        place_piece(board, CHessPiece[player], make_move(board, player, AI_turn))
        if check_win(board, CHessPiece[player]):
            print(f"{player} 赢了！")
            break
        if not AI_turn:
            AI_turn = True
        else:
            AI_turn = False
        player = 'X' if player == 'O' else 'O'

if __name__ == "__main__":
    main()