Therefore,+dropping+out+of+school+is+worth+it+when+there+is+a+satisfactory+job.有没有错误

时间: 2023-12-12 07:35:29 浏览: 30
根据提供的引用内容,无法判断Therefore, dropping out of school is worth it when there is a satisfactory job是否有错误。因为这句话与引用内容没有任何关联,无法判断其是否正确。但是,从教育和就业的角度来看,通常情况下,完成教育并获得学位可以为未来的职业发展提供更多的机会和更高的薪资。因此,辍学并不是一个值得推荐的选择,除非有特殊的情况或原因。
相关问题

Your branch is based on 'origin/zw/1.2.6-dropping-probability', but the upstream is gone.

I understand that you are facing an issue with your branch. If the upstream branch 'origin/zw/1.2.6-dropping-probability' no longer exists, you can follow these steps to resolve the issue: 1. Check if you have any local commits that are not pushed to the remote repository. If yes, create a backup of those commits by creating a new branch or applying a patch. 2. Reset your branch to the last known good commit by using the following command: ``` git reset --hard <commit-hash> ``` Replace `<commit-hash>` with the hash of the last known good commit. 3. If you have created a backup branch in step 1, you can cherry-pick or apply the patch to reapply your local commits. 4. If you don't have any local commits to preserve, you can delete your branch and recreate it from the updated upstream branch or another appropriate branch. Remember to consult with your team members or project maintainers before making any significant changes to avoid any conflicts or disruptions in your workflow.

Take a screenshot and submit it, make sure the inplace parameter is set to True

I'm sorry, as an AI language model, I don't have the capability to take screenshots as it requires access to a graphical user interface (GUI). However, I can provide you with the code snippet to set the `inplace` parameter to `True` when modifying a dataframe in Pandas. The `inplace` parameter is a boolean parameter that specifies whether to modify the dataframe in place or return a new modified copy of the dataframe. When `inplace=True`, the dataframe will be modified in place and the original dataframe will be updated. When `inplace=False` (the default), the dataframe will not be modified in place and a new modified copy of the dataframe will be returned. Here is an example code snippet that modifies a dataframe in place by dropping a column and setting `inplace=True`: ``` import pandas as pd # create a sample dataframe df = pd.DataFrame({'A': [1, 2, 3], 'B': [4, 5, 6], 'C': [7, 8, 9]}) # drop a column in place by specifying the column name and inplace=True df.drop('C', axis=1, inplace=True) # print the resulting dataframe print(df) ``` This will output the following dataframe with the 'C' column dropped: ``` A B 0 1 4 1 2 5 2 3 6 ``` Note that when `inplace=True`, the drop() method modifies the original dataframe `df` directly, and there is no need to assign the result back to `df`.

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将下列代码变为伪代码def median_target(var): temp = data[data[var].notnull()] temp = temp[[var, 'Outcome']].groupby(['Outcome'])[[var]].median().reset_index() return temp data.loc[(data['Outcome'] == 0 ) & (data['Insulin'].isnull()), 'Insulin'] = 102.5 data.loc[(data['Result'] == 1 ) & (data['Insulin'].isnull()), 'Insulin'] = 169.5 data.loc[(data['Result'] == 0 ) & (data['Glucose'].isnull()), 'Glucose'] = 107 data.loc[(data['Result'] == 1 ) & (data['Glucose'].isnull()), 'Glucose'] = 1 data.loc[(data['Result'] == 0 ) & (data['SkinThickness'].isnull()), 'SkinThickness'] = 27 data.loc[(data['Result'] == 1 ) & (data['SkinThickness'].isnull()), 'SkinThickness'] = 32 data.loc[(data['Result'] == 0 ) & (data['BloodPressure'].isnull()), 'BloodPressure'] = 70 data.loc[(data['Result'] == 1 ) & (data['BloodPressure'].isnull()), 'BloodPressure'] = 74.5 data.loc[(data['Result'] == 0 ) & (data['BMI'].isnull()), 'BMI'] = 30.1 data.loc[(data['Result'] == 1 ) & (data['BMI'].isnull()), 'BMI'] = 34.3 target_col = [“Outcome”] cat_cols = data.nunique()[data.nunique() < 12].keys().tolist() cat_cols = [x for x in cat_cols ] #numerical列 num_cols = [x for x in data.columns if x 不在 cat_cols + target_col] #Binary列有 2 个值 bin_cols = data.nunique()[data.nunique() == 2].keys().tolist() #Columns 2 个以上的值 multi_cols = [i 表示 i in cat_cols if i in bin_cols] #Label编码二进制列 le = LabelEncoder() for i in bin_cols : data[i] = le.fit_transform(data[i]) #Duplicating列用于多值列 data = pd.get_dummies(data = data,columns = multi_cols ) #Scaling 数字列 std = StandardScaler() 缩放 = std.fit_transform(数据[num_cols]) 缩放 = pd。数据帧(缩放,列=num_cols) #dropping原始值合并数字列的缩放值 df_data_og = 数据.copy() 数据 = 数据.drop(列 = num_cols,轴 = 1) 数据 = 数据.合并(缩放,left_index=真,right_index=真,如何 = “左”) # 定义 X 和 Y X = 数据.drop('结果', 轴=1) y = 数据['结果'] X_train, X_test, y_train, y_test = train_test_split(X, y, train_size=0.8, shuffle=True, random_state=1) y_train = to_categorical(y_train) y_test = to_categorical(y_test)

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